Symfony3中的一个控制器中有多种形式

Question

I'm trying to use two forms in one controller. Each of them uses diffrent entity. Everytime i try to use second form, the first one executes. How to make it right?

    $document = new Document();

    $form2 = $this->createFormBuilder($document)
        ->add('file', FileType::class, array('label' => 'Wgraj plik '))
        ->add('name', TextType::class, array('label' => 'Nazwa dodawanego pliku'))
        ->add('toFill', CheckboxType::class, array('label' => 'Do wypełnienia?', 'required' => false))
        ->add('save', SubmitType::class, array('label' => 'Dodaj plik'))
        ->getForm();


    if ($form2->handleRequest($request)->isValid() && $form2->isSubmitted()) {
        $em = $this->getDoctrine()->getManager();

        $document->upload();
        $document->setFormId($id);

        $em->persist($document);
        $em->flush();


    }

    $raportFiles = new RaportFiles();

    $formRaportsInput = $this->createFormBuilder($raportFiles)
        ->add('file', FileType::class, array('label' => 'Wgraj plik '))
        ->add('name', TextType::class, array('label' => 'Nazwa dodawanego pliku'))
        ->add('save', SubmitType::class, array('label' => 'Dodaj plik'))
        ->getForm();


    if ($formRaportsInput->handleRequest($request)->isValid()) {
        $em = $this->getDoctrine()->getManager();

        $raportFiles->upload();
        $raportFiles->setFormId($id);

            $em->persist($raportFiles);
            $em->flush();
    }

I tried using $this->get('form.factory')->createNamedBuilder() instead, but i can't get it to work.

Answer 1

@Cerad but how to do this in symfony?

Start by defining three routes, one uses GET to display both forms. The other two uses POST to process an individual form.

http://symfony.com/doc/current/routing/requirements.html#adding-http-method-requirements

forms_show:
    path:     /forms
    defaults: { _controller: MyBundle:FormsController:show }
    methods:  [GET]
form_document_post:
    path:     /form-document
    defaults: { _controller: MyBundle:FormsController:documentPost }
    methods:  [POST]
form_raport__files_post:
    path:     /form-raport-files
    defaults: { _controller: MyBundle:FormsController:raportFilesPost }
    methods:  [POST]

Your controller needs three action methods. Lets assume you have made form types just to save some typing.

http://symfony.com/doc/current/forms.html#creating-form-classes

class FormsController {
    public function showAction() {
        $document = new Document();
        $documentForm = $this->createForm(DocumentType::class,$document,array(
            'action' => $this->generateUrl('form_document_post')));

        $raportFiles = new RaportFiles();
        $raportFilesForm = $this->createForm(RaportFilesType::class,$raportFiles,array(
            'action' => $this->generateUrl('form_raport_files_post')));

        // Return the processed template
    }
    // Only gets called when the document form is posted
    public function documentPostAction(Request $request)
    {
        $document = new Document();
        $documentForm = $this>createForm(DocumentType::class,$document);
        $documentForm->handleRequest($document);
        if ($documentForm->isValid()) {
            // Persist
            return $this->redirectToRoute('forms_show');
        }
        // You will have to decide how you want to handle form errors
    }
    // Repeat for second form

Answer 2

You can check if a specific form is submitted by doing this :

$form2->handleRequest($request);    
if ( $form2->isSubmitted() && $form->isValid() ){
    ...
}

$formRaportsInput->handleRequest($request);     
if ( $formRaportsInput->isSubmitted() && $formRaportsInput->isValid() ){
    ... 
}

This will make the job ;)

EDIT : And this is on the same controller action of course !