Simpel Python Calculator - 语法错误 - 缩进错误

Question

I recently started learning Python. I have never coded before, but it seemed like a challenge. The first thing I have made is this calculator. However, I can't seem to get it to work.

while True:
    print("Typ 'plus' to add two numbers")
    print("Typ 'min' to subtract two numbers")
    print("Typ 'multiplication' multiply two numbers")
    print("Typ 'division' to divide two numbers")
    print("Typ 'end' to abort the program")
    user_input = input(": ")

    if user_input == "end"
        break

    elif user_input == "plus":          
        num1 = float(input("Give a number: "))                  
        num2 = float(input("Give another number: "))
        result = str(num1 + num2)                                   
        print("The anwser is: " + str(result))

    elif user_input == "min":
        num1 = float(input("Give a number: "))                  
        num2 = float(input("Give another number: "))            
        result = str(num1 - num2)                                   
        print("The anwser is: " + str(result))

    elif user_input == "maal":
        num1 = float(input("Give a number:"))                   
        num2 = float(input("Give another number: "))            
        result = str(num1 * num2)                                   
        print("The anwser is: " + str(result))

    elif user_input == "deel":
        num1 = float(input("Give a number: "))                  
        num2 = float(input("Give another number: "))            
        result = str(num1 + num2)                                   
        print("The anwser is: " + str(result))

    else:
        print ("I don't understand!")

I know it will probably something stupid, I am still very much learning. Just trying to pickup a new skill instead of bothering my friends who do know how to code.

Answer 1

You missed a colon after an this if statement

if user_input == "end"
    break

Should Be:

if user_input == "end":
    break