简体   繁体   English

Ninject:当属性标记了继承类型时,如何获取继承类型而不是基类型

[英]Ninject : How Get inherited type instead Base type when inherited type marked by attribute

How do I get the inherited type instead of the base type when the inherited type is marked by attribute? 通过属性标记继承的类型时,如何获取继承的类型而不是基本类型?

Can we do it with Ninject or not? 我们可以用Ninject做到吗? Here's what I have: 这是我所拥有的:

static void Main(string[] args)
{
    IKernel kernel = new StandardKernel();

    // use Method which return properly type
    kernel.Bind<IBase>().ToMethod(context => SOMEMETHOD());

    // should be return DerivedClass 
    BaseClass derived = kernel.Get<BaseClass>();
    BaseClass1 derived1 = kernel.Get<BaseClass1>();

    // The result should be:
    derived.WhoIAm();  //--> "DerivedClass"
    derived1.WhoIAm(); //--> "DerivedClass1"
}

// method which resolve this
static object SOMEMETHOD()
{
    // return derived class wich marked by
    // SomeAttribure where base class that which we use in kernel.Get 
}    

Base Classes 基类

class BaseClass : IBase
{    
    public virtual void WhoIAm()
    {
        Console.Write(this.GetType());
    }   
}

class BaseClass1 : IBase
{    
    public virtual void WhoIAm()
    {
        Console.Write(this.GetType());
    }   
}

Inherited Classes. 继承的类。 SomeAttribute is an attribute that marks the type that should be created SomeAttribute是一个属性,用于标记应创建的类型

[SomeAttribute]
class DerivedClass : BaseClass
{
    public override void WhoIAm()
    {
        Console.Write(this.GetType());
    }
}    

Other Derived classes inheriting from BaseClass1 BaseClass1继承的其他派生类

[SomeAttribute]
class DerivedClass1 : BaseClass1
{
    public override void WhoIAm()
    {
        Console.Write(this.GetType());
    }
}    
class SomeAttribute : Attribute {}

interface IBase
{
    void WhoIAm();
}

Look at the convention extension. 查看约定扩展。 Should be straight forward. 应该直截了当。 Something like 就像是

kernel.Bind(x =>
{
    x.FromThisAssembly()
     .SelectAllClasses()
     .WithAttribute<SomeAttribute>()
     .BindBase();
});

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM