Python的方式来拆分字符串，然后再次拆分结果？

Question

Is there a more pythonic way to do this

def parse_address(hostname, addresses):
    netmask=''
    for address in addresses:
        if hostname in address:
            _hostname, _netmask = address.strip().split('/')
            hostname = _hostname.split()[-1]
            netmask = '/' + _netmask.split()[0]
            break

    return netmask

Test case

If you do TDD

def test_parse_netmask(self):
        hostname = '127.0.0.1'

        stdout = [
            "1: lo    inet 127.0.0.1/8 scope host lo\       valid_lft forever preferred_lft forever",
            "3: wlp4s0    inet 192.168.2.133/24 brd 192.168.2.255 scope global dynamic wlp4s0\       valid_lft 58984sec preferred_lft 58984sec",
            "4: docker0    inet 172.17.0.1/16 scope global docker0\       valid_lft forever preferred_lft forever",
            "5: br-a49026d1a341    inet 172.18.0.1/16 scope global br-a49026d1a341\       valid_lft forever preferred_lft forever",
            "6: br-d26f2005f732    inet 172.19.0.1/16 scope global br-d26f2005f732\       valid_lft forever preferred_lft forever",
        ]

        netmask = scanner.parse_address(hostname, stdout)

        self.assertEqual(netmask, '/8')

Answer 1

def x(hostname,addresses):
    import re 
    for address in addresses:
        result = re.search(hostname+r"/\d", address)
        if result:
            return result.group(0).split(hostname)[1]

Don't know if it's more 'Pythonic' but I would do it this way. It's readable to others, yet it's short enough to not drag on the function.

Answer 2

import re
hostname = '127.0.0.1'
stdout = [
            "1: lo    inet 127.0.0.1/8 scope host lo\       valid_lft forever preferred_lft forever",
            "3: wlp4s0    inet 192.168.2.133/24 brd 192.168.2.255 scope global dynamic wlp4s0\       valid_lft 58984sec preferred_lft 58984sec",
            "4: docker0    inet 172.17.0.1/16 scope global docker0\       valid_lft forever preferred_lft forever",
            "5: br-a49026d1a341    inet 172.18.0.1/16 scope global br-a49026d1a341\       valid_lft forever preferred_lft forever",
            "6: br-d26f2005f732    inet 172.19.0.1/16 scope global br-d26f2005f732\       valid_lft forever preferred_lft forever",
        ]

print [item.split('/')[-1] for item in re.findall(r'(?:\d+\.){3}\d+\/\d+',''.join(stdout)) if hostname  in item]

['8']

Answer 3

Would you be able to base it on code like this?

from urllib.parse import urlparse

parseResult = urlparse('http://www.fake.ca/185')
print ( parseResult )

parseResult is a structure with elements that are revealed in the output of the print statement.

ParseResult(scheme='http', netloc='www.fake.ca', path='/185', params='', query='', fragment='')