提高效率以从Java中的字符串中删除字符

Question

--> How can I improve "efficiency of removing a character from a string" in the following code:

import java.util.Scanner;

public class StringPractice {

public static void main(String[] args) {
    Scanner sc=new Scanner(System.in);
    System.out.println("Enter a String : ");
    String str;
    str=sc.nextLine();
    System.out.println("Enter char to remove : ");
    char ch=sc.nextLine().charAt(0);

    char[] a=new char[str.length()];
//  System.out.println("Parameters : Char : "+ch+"  String : "+str+"\n");

    StringPractice ob=new StringPractice();
    a=ob.removeChar(str,ch);
    String str1=new String(a);
    System.out.println("New String is : "+str1);
}
char[] removeChar(String a,char c){
    char[] ch=new char[a.length()];
    byte count=0;
    for(int i=0;i<a.length();i++){
        if(a.charAt(i)==c){
            count++; 
            continue;
        }
         ch[i-count]=a.charAt(i);
    }

    return ch; 
}
}

Answer 1

According to me you are writing code to remove a character occurrence from a sting so just replace it with empty string: Just change this code there is no need of removeChar method:

StringPractice ob=new StringPractice();
        a=ob.removeChar(str,ch);
        String str1=new String(a);

SOl:

str = str.replace(ch, "");

To replace All Occurrence:

 str = str.replaceAll("ch","");

Answer 2

inbuilt String function replaceAll() to remove all the occurrences and replace() to remove single character.

 string = string.replaceAll("c","");
 string = string.replace("c","");

Answer 3

You can also use the StringBuilder class which is mutable.

StringBuilder sb = new StringBuilder(inputString);

 public class RemoveString { public static void main (String args[]){ StringBuilder name= new StringBuilder("chandu"); int i= name.indexOf("n"); name.deleteCharAt(i); System.out.println(name.toString()); }