$ .post（）数据到Codeigniter 3
[英]$.post() data to Codeigniter 3
问题描述
I have an $.post() and i want receive the data into my controller, how could i do that? 
我有一个$.post() ，我想将数据接收到我的控制器中，我该怎么做？
jQuery jQuery的
$.post($('#url').val() + "Dashboard/getApi", { name: "John", time: "2pm" })
.done(function( data ) {
alert( "Data Loaded: " + data );
});
vvvvvvvvvvvvvvvvvvv this is my url vvvvvvvvvvvvvv
$('#url').val() + "Dashboard/getApi" = "http://127.0.0.1/M2MWare/Dashboard/getApi"
And this is my controller 这是我的控制器
function getApi()
{
$valores = $this->input->post();
// print_r($valores);
return json_encode($valores);
}
this returns me an empty array, i tried with different url, data and nothing why? 这返回了一个空数组，我尝试使用不同的url，数据，但是为什么呢？
1 个解决方案
解决方案1
0 2016-10-07 12:25:54
Codeigniter 3.1.0 running on WampServer. 在WampServer上运行的Codeigniter 3.1.0。
The Dashboard Controller 仪表板控制器
<?php
defined('BASEPATH') OR exit( 'No direct script access allowed' );
class Dashboard extends CI_Controller {
public function __construct() {
parent::__construct();
}
public function index() {
$this->load->view('post_view');
}
function getApi() {
$valores = $this->input->post();
echo json_encode($valores);
}
}
The View post_view.php This is Very Bare Bones for simplicity. 视图post_view.php为简单起见，这是非常裸露的骨头。
<html lang="en">
<head>
<title>Post Me</title>
</head>
<body>
<form>
<input type="hidden" id="url" value="http://ci310tut.com/">
</form>
<script src="<?= base_url('assets/js/jquery.min.js'); ?>"></script>
<script>
$(document).ready(function () {
console.log('We should be seeing an alert popup');
$.post($('#url').val() + "Dashboard/getApi", {name: "John", time: "2pm"})
.done(function (data) {
alert("Data Loaded: " + data);
});
});
</script>
</body>
</html>
And from the above I get an alert screaming at me each time I perform a page refresh with the provided data being displayed. 从以上内容可以看到，每次执行页面刷新并显示提供的数据时，我都会大叫一声。
So you might want to check the above against what you have. 因此，您可能想要对照所拥有的内容检查以上内容。
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