使用外部属性运行 Jar 文件

Question

I have jar file that I want to run along with specific properties file. I am running following command to execute that jar

java –jar –DApp.config.file=local.properties App.jar

With this command I am getting following error

Could not load properties from class path resource [local.properties]: class path resource [local.properties] cannot be opened because it does not exist

Based on what I read so far if you are passing -jar then you don't have to worry about $CLASSPATH. Am I missing something here ?

PS - local.properties and jar files are in same directory.

Answer 1

The -jar option specifies the jar file to launch, hence, has to remain right before the naming of the intended jar file:

java –DApp.config.file=local.properties –jar App.jar

Don't place other options between –jar and App.jar

Answer 2

您可以使用以下代码片段来访问外部属性文件并运行您的 jar 文件：

java -jar jarname.jar --spring.config.location=/path/to/propertyfile.properties

Answer 3

To load properties as a classpath resource it needs to be on the classpath. If you're running with -jar then everything either needs to be in the jar or you need to play manifest games.

If you want to load properties from an external file then load it as a file, not a classpath resource.