[英]Ruby On Rails - Coverting a JOIN using HAVING to a scope
I tried to ask this question previously and it didn't go well - hopefully I do it better this time. 我以前曾尝试问过这个问题,但进展不顺利-希望这次我做得更好。
I have three models 我有三种模式
class Flavor < ActiveRecord::Base
has_many :components
has_many :ingredients, through: :components
end
class Ingredient < ActiveRecord::Base
has_many :components
has_many :flavors, through: :components
end
class Component < ActiveRecord::Base
belongs_to :ingredient
belongs_to :flavor
validates :percentage, presence: true
end
Batches are made of flavors, but a flavor can only be made into a batch if it's components add up to 100 percent (hence why I put the percentage validation in there so it was represented). 批次是由调味料制成的,但是只有当调味料的成分加起来达到100%时,才可以将其制成批次(因此,为什么要在其中放置百分比验证以便如此表示)。
At first I tried to write this as a scope, but could never get it to work, the model testing i created worked using 最初,我尝试将其编写为作用域,但无法使其正常工作,我创建的模型测试可以使用
def self.batch_eligible
self.find_by_sql("Select flavors.* FROM flavors
INNER JOIN components on flavors.id = components.flavor_id
GROUP BY flavors.id, flavors.name
HAVING SUM(percentage)=100")
end
I did make an attempt at the scope and it failed. 我确实尝试过示波器,但失败了。 Here is the final version of the scope I came up with:
这是我想出的范围的最终版本:
scope :batch_eligible, -> {joins(:components).having('SUM(percentage) = 100').group('flavor.id')}
The resultant object will be used to populate a selection list in a form for batches (flavors can exist before the components are fully worked out). 生成的对象将用于以批次的形式填充选择列表(味道可能在组件完全加工之前就存在)。
I figure the limitation here is my understanding of scopes - so how would the scope be built properly to produce the same results as the find_by_sql expression? 我认为这里的限制是我对范围的理解-那么如何正确构建范围以产生与find_by_sql表达式相同的结果?
All help is appreciated, thanks. 感谢所有帮助,谢谢。
In response to the first comment - I tried a variety of scopes without capturing the errors - the scope above returns this error: 作为对第一条评论的回应-我尝试了多种范围而不捕获错误-上面的范围返回了此错误:
ActiveRecord::StatementInvalid:
PG::UndefinedTable: ERROR: missing FROM-clause entry for table "flavor"
LINE 1: SELECT COUNT(*) AS count_all, flavor.id AS flavor_id FROM "f...
^
: SELECT COUNT(*) AS count_all, flavor.id AS flavor_id FROM "flavors" INNER JOIN "components" ON "components"."flavor_id" = "flavors"."id" GROUP BY flavor.id HAVING SUM(percentage) = 100
changing it to flavors id makes it 'work' but it doesn't return the proper information. 将其更改为flavor id使其“可用”,但未返回正确的信息。
One more piece of code - models testing 另一段代码-模型测试
require 'rails_helper'
RSpec.describe Flavor, type: :model do
let!(:flavor) {FactoryGirl.create(:flavor)}
let!(:flavor2) {FactoryGirl.create(:flavor)}
let!(:ingredient) {FactoryGirl.create(:ingredient)}
let!(:component) {FactoryGirl.create(:component, flavor: flavor, ingredient: ingredient, percentage: 25)}
let!(:component1) {FactoryGirl.create(:component, flavor: flavor2, ingredient: ingredient, percentage: 100)}
it "should have a default archive as false" do
expect(flavor.archive).to be(false)
end
it "should only have valid flavors for batch creation" do
expect(Flavor.batch_eligible.count).to eq 1
expect(Flavor.batcH_eligible.first).to eq flavor2
end
end
Even with a clean test database - the batch_eligible count is 4 - not one 即使使用干净的测试数据库-batch_合格的计数为4-不是一个
One more note - the tests DO pass with the find_by_sql function being used - I just think a scope should be possible? 还有一点需要注意-测试必须通过使用find_by_sql函数才能通过-我只是认为范围应该可行?
Props to @taryneast for the help - I was pointed in the right direction by this. 向@taryneast寻求帮助的建议-这样就为我指明了正确的方向。
After correcting the scope issue with flavors.id - I did run the inspect to see what was happening but I also ran a variety of functions. 在用flavors.id纠正了范围问题之后,我确实进行了检查以查看发生了什么,但我还运行了各种功能。
puts Flavor.batch_eligible.count
or puts Flavor.batch_eligible.size
both yield the same thing, for example, the hash {312 => 1} - 312 would be the id of the Factory Created Flavor. puts Flavor.batch_eligible.count
或puts Flavor.batch_eligible.size
都产生相同的结果,例如,哈希{312 => 1} puts Flavor.batch_eligible.size
是工厂创建的Flavor的ID。
So the problem (once I solved flavors.id) wasn't in the scope - it was in the test. 因此,问题(一旦我解决了flavors.id)就不在范围内了,而是在测试中。 You need to test the LENGTH,
Flavor.batch_eligible.length
yields the integer 1 that I wanted. 您需要测试LENGTH,
Flavor.batch_eligible.length
产生我想要的整数1。
Perhaps everyone else knew that - I didn't. 也许其他所有人都知道-我不知道。
Thank you Taryn 谢谢塔琳
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