如何在C＃中使用Neo4jClient在两个节点之间添加关系

Question

public void AddRelationshipTest()
    {
        var conn = Neo4JConn.Connect();
        Team obj = new Team();
        int id1 = 1, id2 = 2;
        NodeReference<Team> sTm = (NodeReference<Team>)ds.GetNodeReference<Team>(id1, conn, obj);
        NodeReference<Team> dTm = (NodeReference<Team>)ds.GetNodeReference<Team>(id2, conn, obj);

        ReportsToData data = new ReportsToData();
        data.SinceYear = 2008;
        reportsTo relation = new reportsTo(dTm, data);
        conn.CreateRelationship(sTm, relation);



    }

where Get NodeRefernce is a method which returns reference of the node and that is working fine. Team is the class having data members as of the nodes When i am using CreateRelationship it creates a relationship My main concern is that it creates relationship even if there is a relationship already between source and target node. I want to create a unique relationship in between two nodes just like

graphClient.Cypher
.Match("(user1:User)", "(user2:User)")
.Where((User user1) => user1.Id == 123)
.AndWhere((User user2) => user2.Id == 456)
.CreateUnique("user1-[:FRIENDS_WITH]->user2")
.ExecuteWithoutResults();

but here FRIENDS_WITH (any relationship) I have to hard code it so i don't want to use it.

How to do it with Neo4jClient?

Answer 1

I'm not really sure what the problem is, with the .CreateUnique why not just use string.Format or string interpolation to not hard code the relationship?

public void CreateRelationship(IGraphClient graphClient, string relationshipName)
{
    graphClient.Cypher
        .Match("(user1:User)", "(user2:User)")
        .Where((User user1) => user1.Id == 123)
        .AndWhere((User user2) => user2.Id == 456)
        .CreateUnique($"(user1)-[:{relationshipName}]->(user2)") //<-- here
        .ExecuteWithoutResults();
}

obviously that could be:

.CreateUnique(string.Format("(user1)-[:{0}]->(user2)", relationshipName))

or even just use + if you really want:

.CreateUnique("(user1)-[:" + relationshipName + "]->(user2)")

You should definitely be using the Cypher technique though, and not using NodeReference<T>