匹配字符串与多层数组

Question

How can i match variable car with variable array? I need to match every first item (Buick, Mercedes, Chevrolet) with my string. I this case should be logged Buick and Chevrolet:

var car = "Buick, Chevrolet";
var array = [
  ["Buick", "2012", "USA", "1201"],
  ["Mercedes", "2005", "Germany", "12354"],
  ["Chevrolet", "1974", "USA", "9401"]
];


if (car = array) {
  console.log("Buick and Chevrolet matches.");  
};

But string could be different - sometimes may be matched items 0, sometimes 30 and so on.

Answer 1

In modern Javascript you use Set and .filter for this:

 var car = "Buick, Chevrolet"; var array = [ ["Buick", "2012", "USA", "1201"], ["Mercedes", "2005", "Germany", "12354"], ["Chevrolet", "1974", "USA", "9401"] ]; var searchCars = new Set(car.match(/\\w+/g)); var found = array.filter(([name]) => searchCars.has(name)); console.log(found); 

Answer 2

You could split the string and iterate for every element and check against the array.

 var car = "Buick, Chevrolet", array = [["Buick", "2012", "USA", "1201"], ["Mercedes", "2005", "Germany", "12354"], ["Chevrolet", "1974", "USA", "9401"]], match = car.split(', ').every(function (a) { return array.some(function (b) { return a === b[0]; }); }); console.log(match); 

 var car = "Buick, Chevrolet", array = [["Buick", "2012", "USA", "1201"], ["Mercedes", "2005", "Germany", "12354"], ["Chevrolet", "1974", "USA", "9401"]], match = car.split(', ').every(function (a) { return array.some(function (b) { return a === b[0]; }); }); if (match) { console.log(car.split(', ').join(' and ') + ' matches.'); } 

Answer 3

You can use reduce() check for element with indexOf()

 var car = "Buick, Chevrolet"; var array = [ ["Buick", "2012", "USA", "1201"], ["Mercedes", "2005", "Germany", "12354"], ["Chevrolet", "1974", "USA", "9401"] ]; var result = array.reduce(function(r, e, i) { if (car.indexOf(e[0]) != -1) { r.push(e[0]); } return r; }, []).join(' and ') + ' matches.'; console.log(result) 

Answer 4

You can use Array.reduce here

 var car = "Buick, Chevrolet"; var array = [ ["Buick", "2012", "USA", "1201"], ["Mercedes", "2005", "Germany", "12354"], ["Chevrolet", "1974", "USA", "9401"] ]; var matches = array.reduce(function(result, item){ if(car.indexOf(item[0]) > -1) result.push(item); return result }, []); console.log(matches) 

Answer 5

You will have to loop over array and you can check for match using string.indexOf()

 var car = "Buick, Chevrolet"; var array = [ ["Buick", "2012", "USA", "1201"], ["Mercedes", "2005", "Germany", "12354"], ["Chevrolet", "1974", "USA", "9401"] ]; var matches = []; var matchesStr = ""; array.forEach(function(item){ if(car.indexOf(item[0]) > -1){ matches.push(item[0]); } }); if(matches.length > 0){ var _last = matches.pop(); matchesStr = matches.toString() + " and " + _last; } else{ matchesStr = matches.toString() } console.log(matchesStr) 

Also, if you have option to update your structure, its better to have array of object instead of array of arrays.

Answer 6

Using array operations filter and map you can produce the desired filtering. First filter the array to get only elements that match the search criteria. Then I map it to extract only data that is required for further operation.

var string = "Buick, Chevrolet";
var cars = [
  ["Buick", "2012", "USA", "1201"],
  ["Mercedes", "2005", "Germany", "12354"],
  ["Chevrolet", "1974", "USA", "9401"]
];

var findCars= function( arr, str ){
   return arr.filter(
         function(s){
              return str.indexOf(s[0])!==-1;
         }
    ).map(
       function(x){
         return x[0];
       }
    );
}

var res = findCars(cars, string);
console.log( res.join(" and ") + " matches.")

If you need the whole matching data item later, then you should skip the mapping of the result and findCars method will look like this:

var findCars= function( arr, str ){
   return arr.filter(
         function(s){
              return str.indexOf(s[0])!==-1;
         }
    );
}

Answer 7

 var car = "Buick, Chevrolet"; var array = [ ["Buick", "2012", "USA", "1201"], ["Mercedes", "2005", "Germany", "12354"], ["Chevrolet", "1974", "USA", "9401"] ]; var result = car .split(', ') .reduce( (res, car) => (array.some(([arrayCar]) => car === arrayCar ? res.push(car) : null), res), []); console.log(`${result.join(' and ')} matches`);