当Catch块中有异常时，继续到ForEach块中的下一个Blob

Question

I have many xmls in Azure Storage container. I wrote code to strip off unnecessary data elements from those xmls. To list all the xmls in different folder structures I used

var blobs = container.ListBlobs(prefix: <Root Location of Blobs>, useFlatBlobListing: true);
 foreach (CloudBlockBlob blob in blobs)

And to parse the xml I am using Linq.

The problem I am facing is there are few xmls that are missing the proper format or few xmls that doesn't have closing literals. I want to catch the exception and skip that xml file from processing and proceed to the next one. How can I do that using the Try catch block ?

The exception I get is System.Xml.XmlException

Answer 1

Try

    foreach (CloudBlockBlob blob in blobs){               
             bool isError = false;   
            try   
            {                          
               // do your code here;   
            }catch(Exception ex){
                isError = true;
            }
           if(isError) continue;
        }

Update:

void Main()

    {
        string[] list = new string[]{"bob", "jack", "tom", "sparrow"};
        foreach(string li in list){
            try{
                if(String.Equals(li, "tom")){
                    throw new Exception("Fault");
                }
                Debug.WriteLine(li);
            }catch(Exception ex){
                Debug.WriteLine(ex.Message);
                continue;
            }
        }
    }

Prints:

bob
jack
Fault
sparrow