如何在我的 Android 应用程序中打开来自其他应用程序的链接

Question

I want to open an external link in my app.

For example when the user clicks on www.example.com/batmanpage from instagram I want to open this page (Batman page) in my application, as a deep link.

How can I do it?

Answer 1

Just google "Android deep link". You will get for example:

this link

Be careful about the details or your deep link won't work.

<activity
    android:name="com.example.android.GizmosActivity"
    android:label="@string/title_gizmos" >
    <intent-filter android:label="@string/filter_title_viewgizmos">
        <action android:name="android.intent.action.VIEW" />
        <category android:name="android.intent.category.DEFAULT" />
        <category android:name="android.intent.category.BROWSABLE" />
        <!-- Accepts URIs that begin with "http://www.example.com/gizmos” -->
        <data android:scheme="http"
              android:host="www.example.com"
              android:pathPrefix="/gizmos" />
        **<!-- note that the leading "/" is required for pathPrefix-->**
        <!-- Accepts URIs that begin with "example://gizmos” -->
        <data android:scheme="example"
              android:host="gizmos" />

    </intent-filter>
</activity>

In the activity you need to read the values from the intent:

@Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.main);

    Intent intent = getIntent();
    String action = intent.getAction();
    Uri data = intent.getData();
}

If your Activity is not "standard" and if an instance has already been created you will receive the intent in the onNewIntent method.