[英]regex replace only a part of the match
I want to replace only a part of the string of a regex pattern match. 我想只替换正则表达式模式匹配的一部分字符串。 I found this answer but I don't get it... 我找到了这个答案,但我没有得到它......
How do I use substitution? 我如何使用替代?
Example of what I want: keep the first slug digit, only replace others 我想要的例子:保留第一个slug数字,只替换其他数字
/09/small_image/09x/
> /09/thumbnail/
/09/small_image/09x/
> /09/thumbnail/
1st: unknown digit
第1名: unknown digit
2nd: "small_image"
第二名: "small_image"
3rd: unknown digit + "x"
第3名: unknown digit + "x"
Here is what I have so far: 这是我到目前为止:
var regexPattern = /\/\d\/small\_image\/\d*x/;
var regexPattern = /\/\d\/(small\_image\/\d*x)$1/; ??
var result = regexPattern.test(str);
if (result) {
str = str.replace(regexPattern, 'thumbnail');
}
var input = "/09/small_image/09x/"; var output = input.replace(/(\\/\\d+\\/)small_image\\/\\d*x/, "$1thumbnail"); console.log(output);
Explanation: 说明:
Put the part you want to keep in parentheses, then refer to that as $1
in the replacement string - don't put $1
in your regex. 把你想要保留的部分放在括号中,然后在替换字符串中将其称为$1
- 不要在你的正则表达式中$1
。 So (\\/\\d+\\/)
means to match a forward slash followed by one or more digits, followed by another forward slash. 所以(\\/\\d+\\/)
表示匹配正斜杠后跟一个或多个数字,后跟另一个正斜杠。
(Note that you don't need to escape underscores in a regex.) (请注意,您不需要在正则表达式中转义下划线。)
Go with 跟着去
var regexPattern = /(\/\d+\/)small\_image\/\d*x/;
and 和
str = str.replace(regexPattern, '$1thumbnail');
First , you were missing the +
. 首先 ,你错过了+
。 Because 09
are two digits, you need the regexp to match one or more digits ( \\ḑ
would be exactly one). 因为09
是两位数,所以你需要正则表达式来匹配一个或多个数字( \\ḑ
就是一个数字)。 This is accomplished by \\d+
这是通过\\d+
完成的
Second , everything you match is being removed at first. 其次 ,首先要删除你匹配的所有内容。 To get the /09/
part back afterwards, you have to remember it by putting it into brackets in the regexp (
... )
and afterwards reference it in the replacement via $1
要在之后恢复/09/
部分,您必须通过将其放入正则表达式(
... )
中的括号中来记住它,然后通过$1
在替换中引用它
One could as well create other groups and reference them by $2
, $3
... 还可以创建其他组,并以$2
$3
$2
引用它们......
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