试图获得对象的唯一列表

Question

I have a collection of objects

var array = 
[
    {"category":"A", "categoryname":"somename", key: 1, description: "something"}, 
    {"category":"A", "categoryname":"somename", key: 1, description: "something"}, 
    {"category":"B", "categoryname": "somename", key: 1, description: "something"}
    {"category":"B", "categoryname": "somename", key: 3, description: "something"}
    {"category":"C", "categoryname": "somename", key: 2, description: "something"}
    {"category":"C", "categoryname": "somename", key: 2, description: "something"}
]

that have 4 values (category, categoryname, key, description) and I need to loop through it and get a unique list of objects based on the category. But I want to return the unique list with 2 preoperties and not just one. If I use

_.uniq(_.pluck(array,"category"))

this gives me what I want except I need the categoryname as well as the category. Is this possible?

Answer 1

There are a couple of questions on the same use case already.

Plucking Multiple Properties

Removing duplicate objects with Underscore for Javascript

Answer 2

You can use $.unique() , Array.prototype.map() , JSON.stringify() , JSON.parse()

 var array = [{ "category": "A", "categoryname": "somename", key: 1, description: "something" }, { "category": "A", "categoryname": "somename", key: 1, description: "something" }, { "category": "B", "categoryname": "somename", key: 1, description: "something" }, { "category": "B", "categoryname": "somename", key: 3, description: "something" }, { "category": "C", "categoryname": "somename", key: 2, description: "something" }, { "category": "C", "categoryname": "somename", key: 2, description: "something" }]; var res = $.unique(array.map(function(el) { return JSON.stringify([el.category, el.categoryname]) })).map(JSON.parse); console.log(res); 

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