搜索file1中包含的字符串中未找到的字符串

Question

I'm trying to run a search command to lookup strings from file1 and find them in file2. I then want to print ONLY the strings from file1 that are NOT FOUND in file2.

File1 would be something like:

 read
 write
 access

File2 would be:

0xFF88 T write
0xFF87 t xyzwrite
0xFF86 T read
0xFF85 T xyzread
0xFF84 T xyzaccess

So the desired result would be:

 access

*** Note, I did add a blank to all of the strings in File1 in order to not include every occurrence of the string which is part of another string.

I've tried:

grep -vf file1 file2 

and get results from file2 that are all but the write and read lines, addresses included.

I've tried:

grep -vf file2 file1 

and get all of file1 because a whole line of file2 never appears in file1.

I've tried:

diff file1 file2 | grep \^|<

and get all of file1 proceeded with < on each line.

I was told that if I could remove the first 8 characters of each line in file2 then the diff/grep commands would work.

I've also tried findstr (Windows) with various options and again, I can't get it to work.

Also, please note that each file has many more lines than I've shown.

Any ideas?

Answer 1

You probably have to do a loop:

for i in $(cat File1); do
  grep -q "\<$i\$" File2 || echo $i
done

This will print out:

access