[英]Tornado how to return error exception?
I want to run a method I know this method doesn't work and I want to get the error returned by the method.我想运行一个方法,我知道这个方法不起作用,我想得到该方法返回的错误。
This is my code :这是我的代码:
def is_connect(s):
print("ok connection")
print(s)
ioloop.stop()
try:
current_job_ready = 0
print("ok1")
beanstalk = beanstalkt.Client(host='host', port=port)
print("ok1")
beanstalk.connect(callback=is_connect)
ioloop = tornado.ioloop.IOLoop.instance()
ioloop.start()
print("ok2")
except IOError as e:
print(e)
And this is the error I have when I run my program with wring port :这是我使用 wring port 运行程序时遇到的错误:
WARNING:tornado.general:Connect error on fd 7: ECONNREFUSED
ERROR:tornado.application:Exception in callback <functools.partial object at 0x7f5a0eac6f18>
Traceback (most recent call last):
File "/usr/local/lib/python2.7/dist-packages/tornado/ioloop.py", line 604, in _run_callback
ret = callback()
File "/usr/local/lib/python2.7/dist-packages/tornado/stack_context.py", line 275, in null_wrapper
return fn(*args, **kwargs)
File "/usr/local/lib/python2.7/dist-packages/tornado/ioloop.py", line 619, in <lambda>
self.add_future(ret, lambda f: f.result())
File "/usr/local/lib/python2.7/dist-packages/tornado/concurrent.py", line 237, in result
raise_exc_info(self._exc_info)
File "/usr/local/lib/python2.7/dist-packages/tornado/gen.py", line 270, in wrapper
result = func(*args, **kwargs)
TypeError: connect() takes exactly 1 argument (2 given)
I want to have e when I enter a false port or host.当我输入错误的端口或主机时,我想拥有 e。 How can I do this?
我怎样才能做到这一点? I tired to add
raise IOError("connection error")
after beanstalk = beanstalkt.Client(host='host', port=port)
But this force the error, and I just want to have error when it exist.我厌倦了在
beanstalk = beanstalkt.Client(host='host', port=port)
raise IOError("connection error")
之后添加raise IOError("connection error")
但这会强制错误,我只想在错误存在时出现错误。
Here's where reading the code helps.这是阅读代码有帮助的地方。 In beanstalkt 0.6's
connect
, it creates an IOStream to connect to the server:在 beanstalkt 0.6 的
connect
,它创建了一个 IOStream 来连接到服务器:
https://github.com/nephics/beanstalkt/blob/v0.6.0/beanstalkt/beanstalkt.py#L108 https://github.com/nephics/beanstalkt/blob/v0.6.0/beanstalkt/beanstalkt.py#L108
It registers your callback to be executed on success, but if the connection fails it'll just call Client._reconnect
once per second forever.它注册您的回调以在成功时执行,但如果连接失败,它将永远每秒调用一次
Client._reconnect
。 I think you should open a feature request in their GitHub project asking for an error-notification system for connect
.我认为您应该在他们的 GitHub 项目中打开一个功能请求,要求为
connect
提供一个错误通知系统。 With the current beanstalkt implementation, you just have to decide how long you're willing to wait for success:使用当前的 beanstalkt 实现,您只需决定愿意等待成功的时间:
import sys
from datetime import timedelta
from tornado.ioloop import IOLoop
def is_connect(s):
print("ok connection")
print(s)
loop.remove_timeout(timeout)
# Do something with Beanstalkd....
def connection_failed():
print(sys.stderr, "Connection failed!")
# Could call IOLoop.stop() or just quit.
sys.exit(1)
loop = IOLoop.current()
timeout = loop.add_timeout(timedelta(seconds=1), connection_failed)
beanstalk.connect(callback=is_connect)
loop.start()
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