实时获取另一个应用标准输出

Question

I want to get output of console application in realtime (same as run via cmd.exe) by my WinForm application. All actions i perform in non-UI thread (using BackgroundWorker's method bwRezerve_DoWork). AddTextToTextbox use Invoke to update UI.

But now i receive output only when application is exited. I read a lot of question here and on other sites, read similar question Capture output of process synchronously (ie "when it happens") but still can't find solution. Here code snippet:

private void bwRezerve_DoWork(object sender, DoWorkEventArgs e)
{
    proc = new Process
    {
        StartInfo = new ProcessStartInfo
        {
            FileName = Application.StartupPath + Path.DirectorySeparatorChar + "7z.exe",
            Arguments = e.Argument,
            UseShellExecute = false,
            RedirectStandardOutput = true,
            RedirectStandardError = true,
            CreateNoWindow = true,
        }
    };
    proc.EnableRaisingEvents = true;
    proc.OutputDataReceived += (who, what) => AddTextToTextbox(what.Data);
    proc.ErrorDataReceived += (who, what) => AddTextToTextbox(what.Data);

    proc.Start();
    proc.BeginOutputReadLine();
    proc.BeginErrorReadLine();
    //same result with next line commented
    proc.WaitForExit(5 * 60 * 1000);
}

Also i've tried this instead of OutputDataReceived but result is the same

while (!proc.StandardOutput.EndOfStream)
{
    string line = proc.StandardOutput.ReadLine();
    AddTextToTextbox(line);
}

Answer 1

Try this code

private void bwRezerve_DoWork(object sender, DoWorkEventArgs e)
{
    ProcessStartInfo psi = new ProcessStartInfo();
    psi.FileName = Application.StartupPath + Path.DirectorySeparatorChar + "7z.exe";
    psi.Arguments = e.Argument;
    psi.UseShellExecute = false;
    psi.RedirectStandardError = true;
    psi.RedirectStandardOutput = true;
    psi.CreateNoWindow = true;

    Process proc = Process.Start(psi);
    proc.WaitForExit();

    while (!proc.StandardOutput.EndOfStream)
    {
       string line = proc.StandardOutput.ReadLine();
       AddTextToTextbox(line);
    }
}

Answer 2

I think problem there is problem with your thread your process is running under main thread so your output will display only when process is completed. So you need use background worker or thread you can also use dispatcher to get output from current process.

while (!proc.StandardOutput.EndOfStream)
{

  Application.Current.Dispatcher.Invoke(new Action(() =>
     {
    string line = proc.StandardOutput.ReadLine();
    AddTextToTextbox(line);
     }), null);

}

hope its work for you ..

EDIT

you can get current dispatcher using window base Lib.

Assembly: WindowsBase (in WindowsBase.dll) ( Ref MSDN )

System.Windows.Threading.Dispatcher.CurrentDispatcher.Invoke(new Action(() =>
            {
                string line = proc.StandardOutput.ReadLine();
                AddTextToTextbox(line);
            }), null);

Answer 3

7zip doesn't use standard output - you can easily see that since it continually rewrites the screen (to show the progress). There's no way to stream that.