[英]Compress a 2D array into a 1D Array
i have a quad (2D array) which is composed of numbers which ranges from 0 to 255 and the most frequent value of the array ( in my case 2) is the background value 我有一个四边形(2D数组),该数组由范围从0到255的数字组成,并且该数组的最频繁值(在我的情况下为2)是背景值
i have to put all the values of the array except the background value ( i have to ignore all cases that contains a 2) in a 1D array with this arrangement 我必须将除背景值以外的所有数组值(我必须忽略所有包含2的情况)以这种排列方式放置在1D数组中
the line,the column,the value,the line,the next column,the next value 行,列,值,行,下一列,下一个值
for example i have 例如我有
{2,3,2,2},
{2,2,2,2},
in the 1D array it will be like { 1,2,3,}
在一维数组中,它将像
{ 1,2,3,}
i added spaces to make it more readable 我添加了空格以使其更具可读性
here is my array 这是我的数组
int image1[MAXL][MAXC]=
{
{2,3,2,2},
{2,2,2,2},
{2,255,2,2},
{255,2,2,2},
{2,255,2,2}
};
and the loop 和循环
for (int i = 0; i<nbc;i++)
{
for (int j=0; j<nbl;j++)
{
if (image1[j][i]==BackColor)
{
}
else
}
}
nbc and nbl are respectively the number of columns and lines nbc和nbl分别是列数和行数
thanks you for your help 谢谢你的帮助
EDIT : i completely failed my example i didn't ignored the 2, should be fine now 编辑:我完全失败了我的示例,我没有忽略2,现在应该可以了
A simple approach using std::vector
使用
std::vector
简单方法
std::vector<int> result;
for (int i = 0; i<MAXL;i++)
{
for (int j=0; j<MAXC;j++)
{
if (image1[i][j] != BackColor) // Notice !=
{
result.push_back(i+1);
result.push_back(j+1);
result.push_back(image1[i][j]);
}
}
}
for (auto x : result)
{
std::cout << x << " ";
}
std::cout << endl;
Output:
输出:
1 2 3 3 2 255 4 1 255 5 2 255
1 2 3 3 2 255 4 1 255 5 2 255
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