如果按字母顺序，使用Sed仅删除文件名中的第一个字符

Question

I have bunch of files in a folder which I need to copy with another name in case, that if file first charcter is alphabetical, then remove this character and leave all other character asis either those are numbers, alphabeticals, special marks or what ever. So few exsapmles:

R123456.txt --> should be copied as 123456.txt

Y1235465.jpeg --> should be copied as 1235465.jpeg

736628487.txt --> do nothing

I have used this command:

for file in * ; do cp  $file $(echo $file |sed 's/[A-Za-z]//g'); done

But this removes also file extensions which I would like to leave as is...

br Jii

Answer 1

Use

s/^[A-Za-z]//

At the start of the buffer a single alphabetic character

Answer 2

you can also try this;

 for file in * ; do cp -n $file $(echo $file |sed 's/^[A-Za-z]//') 2>/dev/null; done

man cp ; -n, --no-clobber do not overwrite an existing file (overrides a previous -i option)

2>/dev/null : to drop any for "'736628487.txt' are the same file".

Eg:

user@host:/tmp/test/1$ ls
736628487.txt  R123456.txt  Y1235465.jpeg

user@host:/tmp/test/1$  for file in * ; do cp -n $file $(echo $file |sed 's/^[A-Za-z]//') 2>/dev/null; done

user@host:/tmp/test/1$ ls
123456.txt  1235465.jpeg  736628487.txt  R123456.txt  Y1235465.jpeg