在换行前删除空格

Question

I need to remove all spaces before the newline character throughout a string. 我需要删除整个字符串中的换行符之前的所有空格。

string = """
this is a line       \n
this is another           \n
"""

output: 输出：

string = """
this is a line\n
this is another\n
"""

Answer 1

可以拆分串入线，采用剥离右侧所有空格rstrip ，然后在每行的末尾添加一个新行：

''.join([line.rstrip()+'\n' for line in string.splitlines()])

Answer 2

import re
re.sub('\s+\n','\n',string)

Edit: better version from comments: 编辑：评论的更好版本：

re.sub(r'\s+$', '', string, flags=re.M)

Answer 3

As you can find here , 你可以在这里找到，

To remove all whitespace characters (space, tab, newline, and so on) you can use split then join: 要删除所有空白字符（空格，制表符，换行符等），您可以使用拆分然后加入：

sentence = ''.join(sentence.split())

or a regular expression: 或正则表达式：

import re
pattern = re.compile(r'\s+')
sentence = re.sub(pattern, '', sentence)