[英]switch case inside loop
I've run into a slight problem with my function. 我的功能遇到了一个小问题。 When I typed in 8 I want it to quit. 当我输入8时,我希望它退出。 However when I type 8, it prints out my default message then quits. 但是,当我键入8时,它会打印出我的默认消息,然后退出。 What have I missed? 我错过了什么?
void Selection()
{
int selection;
while (selection != 8)
{
printMenu();
scanf("%d", &selection);
switch (selection)
{
case '1': /*FUNCTION HERE*/ ; break;
case '2': /*FUNCTION HERE*/ ; break;
case '3': /*FUNCTION HERE*/ ; break;
case '4': /*FUNCTION HERE*/ ; break;
case '5': /*FUNCTION HERE*/ ; break;
case '6': /*FUNCTION HERE*/ ; break;
case '7': /*FUNCTION HERE*/ ; break;
case '8': break;
default: printf("Unkown command please try again.\n"); break;
}
}
}
The line 线
scanf("%d", &selection);
inputs an int
value, say 8
. 输入一个int
值,例如8
。 But in your case
statement 但是在你的case
case '8': break;
you are testing a character value. 您正在测试一个字符值。 Please change all those case
statements to such as 请将所有这些case
陈述更改为
case 8: break;
Also, you must initialise the local variable selection
before you first test it. 另外,您必须在首次测试之前初始化局部变量selection
。 Compiler should have warned you about that. 编译器应该已经对此发出警告。
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