在Java中返回异常对象

Question

I wrote a custom exception as:

public class CustomException extends Exception {

  public CustomeException(String message) {
    super(message);
  }
}

and try some tests as:

public static String test(String string) throws CustomException {
    if (string == null) {
      throw new CustomException("Empty String");
    }

    return string;
  }

  public static void main(String[] args) throws CustomException {

    String testException = test(null);
    System.out.print(testException);
  }

When I run, it throws the exception. I wonder how can it returns the exception object instead of throwing an exception.

I mean the testExpception object will be CustomExpception when we input the string as null. Can we do it ?

Answer 1

That's for the try catch is designed for.

 public static void main(String[] args) {
    try{
        String testException = test(null);
    }
    catch(CustomException e){// object e can be used for analysing the exception
        e.printStackTrace();
    }

 }

Plus there is a typo in you exception constructor.it should be CustomException not CustomeException and make the same change at other places as well