[英]SQL group by coalesce not working as expected
I have following MySQL table ( images
): 我有以下MySQL表(
images
):
+----+------------+-----------------------+
| id | gallery_id | path |
+----+------------+-----------------------+
| 58 | NULL | 58.jpg
| 59 | NULL | 59.jpg
| 66 | 9 | 9-001.jpg
| 67 | 9 | 9-002.jpg
| 68 | 10 | 10-001.jpg
| 69 | 10 | 10-002.jpg
...
I want to select rows where gallery_id is null or group it by gallery_id if it not null. 我想选择gallery_id为null的行,或者如果不是null则按gallery_id对其进行分组。 So expected result is:
因此,预期结果是:
+----+------------+-----------------------+
| id | gallery_id | path |
+----+------------+-----------------------+
| 58 | NULL | 58.jpg
| 59 | NULL | 59.jpg
| 66 | 9 | 9-001.jpg
| 68 | 10 | 10-001.jpg
...
I tried to use coalesce
function to achieve this result: 我尝试使用
coalesce
功能来实现以下结果:
select * from `images` group by coalesce(gallery_id, id);
But it returns only rows where gallery_id
is null. 但它仅返回
gallery_id
为null的行。 Tell me please what am I doing wrong? 告诉我我在做什么错? Thanks in advance.
提前致谢。
You could use a when in with subselect and group by 您可以使用带子选择和分组依据的when
select * from `images`
where (gallery_id, id ) in (select gallery_id, min(id)
from `images`
where gallery_id is not null
group by gallery_id)
SELECT * FROM `images` where gallery_id is not null group by gallery_id
UNION
SELECT * FROM `images` where gallery_id is null
Your request doesn't make sense. 您的要求没有道理。
GROUP BY
with SELECT *
is non-sensical, because it is unclear where most of the column values come from. 带有
SELECT *
GROUP BY
是没有意义的,因为不清楚大多数列值来自何处。
You seem to want prioritization . 您似乎想确定优先级。 .
。 .
。 one row for each
NULL
and then one for each gallery. 每个
NULL
一行,然后每个图库一行。
I would suggest: 我会建议:
select i.*
from images i
where i.gallery_id is null or
i.id in (select min(i2.id) from images i2 group by i2.gallery_id);
As a bonus, this is standard SQL and should work in any database. 另外,这是标准的SQL,可以在任何数据库中使用。
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