[英]php concating variable and accessing array
is somthing like that possible? 有可能吗?
for ($i = 1; $i <= 15; $i++) {
$var = "bild" . $i;
if (!empty ($row->bild.$i)) {
echo '
<div class="item">
<img border="no" class="bildschatten" src="include/images/projekte/'.$row->bild . $i.'" />
</div>
';
}
}
how should it look correctly? 怎么看起来正确? problem is:
问题是:
I fetch objects from a mysql database, in this table each object has 15 images 我从mysql数据库中获取对象,在这个表中每个对象有15个图像
bild1 .. bild15 bild1 .. bild15
Now I want to iterate over this 15 images and want to check if the colum is empty or not. 现在我想迭代这15张图片,并想检查列是否为空。
the problem I have is here: 我遇到的问题是:
$row->bild.$i
that contains not the value of column bild1.. bild15 ... it only contains the value of $i 它不包含列bild1的值.bild15 ...它只包含$ i的值
thanks 谢谢
You could fetch the result as an array uning 您可以将结果作为数组uning获取
$row = db_fetch_array($result)
and then accessing 然后访问
$var = "bild" . $i;
if (!empty ($row[$var])) {
This is called variable of variables, You need to access something like this $row->$var
. 这被称为变量变量,你需要访问类似
$row->$var
。
Complete Solution: 完整解决方案
for ($i = 1; $i <= 15; $i++) {
$var = "bild" . $i;
if (!empty ($row->$var)) {
echo '
<div class="item">
<img border="no" class="bildschatten" src="include/images/projekte/'.$row->$var.'" />
</div>
';
}
}
这段代码应该有效:
$row->{'bild'.$i}
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