如何将无符号的short存储到char数组中？ C语言

Question

I'm a beginner in C language, I was wondering how I store an unsigned short into a char array?

unit16_t is unsigned short, and below is my code.

uint16_t  combined = 1234;
char echoPrompt[] = {combined};

EDIT:

Sorry for being unclear I need echoPrompt to be a char array and combined needs to be an integer. I am passing echPrompt as a char array to a UART_write which required a char array.

Answer 1

You cannot pass an array to a function. You can pass a pointer. Pointers are not arrays.

If your UART_write looks anything like any of the standard C/POSIX functions write , fwrite etc, you need

  result = UART_write (..., 
        (char*)&combined, 
        sizeof(combined), ...);

There is no need in a char array.

Answer 2

if I understood correctly, you want to save each upper and lower 1 byte of short in char array.

well, why don't you just use union?

typedef struct uint16_s{ 
    char upper; 
    char lower;
} uint16_s;

typedef union uint16_u{
    uint16_s sBuf;
    uint16_t tBuf;
} uint16_u;

uint16_u combined;
combined.tBuf = 1234;
char echoPrompt[] = {combined.sBuf.upper, combined.sBuf.lower};