带有元组的非常简单的函数（python）

Question

I know this is really easy but I can't understand how to code at all. So I need to create two functions (if you can only help me with one that's fine):

Function a which receives a positive integer and transforms it into a tuple, like this:

>>>a(34500)
(3, 4, 5, 0, 0)
>>>a(3.5)
ValueError: a: error

And function b which receives a tuple and transforms it into an integer, like this:

>>>b((3, 4, 0, 0, 4))
34004
>>>b((2, ’a’, 5))
ValueError: b: error

I haven't learned much yet, only functions, while and for cycles, tuples, raise and isinstance(for the error message?), and probably some other things. I've tried looking for answers but they all used things I haven't learned.

Answer 1

def to_tuple(input_number):
    # check if input number is int or not
    if isinstance(input_number,(int)):
        # convert number to string
        to_string = str(input_number)
        # finally convert string to
        # list of numbers followed by converting the list to tuple
        tuple_output = tuple(map(int,to_string))
        return tuple_output
    # if not int return empty tuple
    # well coz nobody likes useful but ugly python tracebacks
    else:
        return ()

# lets see example
number = 3450
print to_tuple(number)
(3, 4, 5, 0)

number = 353984
print to_tuple(number)
(3, 5, 3, 9, 8, 4)

number = 2.6
print to_tuple(number)
()

If you like this example I'd post answer for the second part

Answer 2

The comments already state what you can do: Convert the int to str by doing (I know this does not work for floats, here you can show some further effort:))

for c in str(integerVariable):
    print c

The other way around is even more simple.

''.join(tupleVariable)

Answer 3

Try this

def a(n):
result = []

while n > 0:
    result.append(n%10)
    n=n//10

return tuple(reversed(result))

for question 2, try doing the same thing in reverse ie multiplying each number by 1, 10, 100 and adding them up.

also don't forget error checking code.