如何使用 sender.titleForState(.Normal) 获取 Swift 3.0、ios 中按钮的当前标题！

Question

I tried to get the title of a button in swift like below.

@IBAction func buttonAction(_ sender: Any) {
  let buttonTitle = sender.titleForState(.Normal)!
}

but it didn't work,even it doesn't give any hint when we press . after the sender.

so what is the correct way of doing this in swift 3.0

Or else if we create an IBOutlet and then we use its currentTitle , it works fine like below. Why we cannot get it with sender. for above

@IBOutlet var thebutton: UIButton!

@IBAction func buttonAction(_ sender: Any) {
  let buttonTitle = thebutton.currentTitle!
  print(buttonTitle)
}

Answer 1

Because parameter sender is in type Any instead of UIButton . Change the method signature to:

@IBAction func buttonAction(_ sender: UIButton) {
  if let buttonTitle = sender.title(for: .normal) {
    print(buttonTitle)
  }
}

and you should be good to go.

Answer 2

To get the title of the button regardless of its current state in swift 3.0 try using this:

    @IBAction func buttonPressed(_ sender:UIButton){
       let buttonTitle = sender.titleLabel?.text
       print("\(String(describing: buttonTitle)")
    }

This will return the title for the state, based on the state that the button is current in.

Answer 3

Smartest version using Swift 5.0:

@IBAction func buttonAction(_ sender: UIButton) {
    print(sender.currentTitle)
}

Answer 4

In order to resolve the warning, following code may be used.

@IBAction func buttonAction(_ sender: UIButton) {
      let buttonTitle = sender.title(for: .normal) ?? String()
      print(buttonTitle)
    }

Answer 5

Since Swift 3.0, it changed from

sender.titleForState(.Normal)! >> sender.title(for : .normal)!

Change Any to AnyObject .

@IBAction func buttonPressed(_ sender: AnyObject) {
  let title = sender.title(for: .normal)!
  print("\(title) button pressed")
}

Answer 6

@IBAction func buttonPressed(_ sender: AnyObject) {
  let title = sender.title(for: .normal)
  print("\(title) button pressed")
}

So this is for swift 4.0, not the last one.

Answer 7

If your button has a regular title you can use:

button.title(for: state) // probably UIControl.State.normal

If your UIButton has an attributed title you'll need to use:

self.attributedTitle(for: state)

Or you can use a more general extension:

extension UIButton {
    func titleForState(_ state: UIControl.State = .normal) -> String? {
        if let title = self.title(for: state) {
            return title
        }

        if let attribTitle = self.attributedTitle(for: state) {
            return attribTitle.string
        }

        return nil
    }
}

Answer 8

Using Swift version 5.5.2, the best way I found out to print a label's title is:

@IBAction func keyPressed(_ sender: UIButton) {
    print(sender.title(for: .normal)!)
}

I was receiving a warning while using sender.title(for: .normal) . The exclamation mark (!) solved it.

Answer 9

I used switch statment:

var buttonConter = 1
@IBAction func hardlessSelected(_ sender: UIButton) {

    switch buttonConter {
    case 1:
        buttonConter += 1
        print("Soft")
    case 2:
        buttonConter += 1
        print("Medium")
    case 3:
        buttonConter += 1
        print("Hard")
    default:
        print("Non")
    }

    
}

}

Answer 10

The simple way just to use currentTitle:

@IBAction func hardlessSelected(_ sender: UIButton) {

    print(sender.currentTitle)
}

Answer 11

  @IBAction func btnNextTapped(_ sender: Any) {
    let title = (sender as AnyObject).title(for: .normal)!
  }

Swift4.0