SQL Server，如何获取多个不同的项目

Question

I am using SQL server,

  id          3     | 4    | 5 | 6
  items       1 2 3 | 2 3 5| 6 | 1 2 5
    -------------------------
  # of items      3 | 4    | 5 | 5

so, each id has items (ex, 3 has 3 items - 1,2,3) and for each item, I'd like to get the number of distinct items accrued.

so, 3 has 3 distinct items - 1, 2, 3
4 has 4 distinct items - 1, 2, 3, 5
5 has 5 distinc items - 1, 2, 3, 5, 6
6 has 5 distinct items - 1, 2, 3, 5, 6

I can do this by running, 1 through 2, 1 though 3, 1 through 5 and 1 through 6 by doing count(distinct items) But I want to automate this process and get the same results in one run.

The idea is to create a temp table and put an item in it while checking if the item is already in the temp table and print number of distinct items for each id.

Answer 1

CREATE TABLE TEST
(
    id int, items int
)

INSERT INTO TEST
VALUES
(3, 1),
(3, 2),
(3, 3),
(4, 2),
(4, 3),
(4, 5),
(5, 6),
(6, 1),
(6, 2),
(6, 5)

SELECT B.id, COUNT(DISTINCT(A.ITEMS)) AS itemCount
FROM TEST A
INNER JOIN TEST B ON A.id <= B.id
GROUP BY B.ID

DROP TABLE TEST

Output: 
id  itemCount
3   3
4   4
5   5
6   5

Answer 2

Assuming your data in below format:

Declare @table table
(
id int,
items varchar(10)
)

insert into @table values (3, '1 2 3');
insert into @table values (4, '2 3 5');
insert into @table values (5, '6');
insert into @table values (6, '1 2 5');

with cte as
(
Select id, b.Item
from @table a
cross apply [dbo].[Split] (items, ' ') b
)

Select y.id, count(distinct(x.Item)) AS [# of items]
from cte x
join cte y on x.id <= y.id
group by y.id

Use the table valued function [dbo].[Split] from LINK .

Answer 3

You can as the below:

DECLARE @Tbl TABLE (Id VARCHAR(10), Column3 VARCHAR(100), Column4 VARCHAR(100), Column5 VARCHAR(100), Column6 VARCHAR(100))
INSERT @Tbl
VALUES 
('items', '1 2 3', '2 3 5', '6', '1 2 5')   

;WITH CTE1
AS
(
    SELECT T.Id, T.Column3 AS ColumnId, CAST('<X>' + REPLACE(T.Column3,' ','</X><X>') + '</X>' as XML) AS FilterColumn FROM  @Tbl T UNION ALL
    SELECT T.Id, T.Column4 AS ColumnId, CAST('<X>' + REPLACE(T.Column4,' ','</X><X>') + '</X>' as XML) AS FilterColumn FROM  @Tbl T UNION ALL
    SELECT T.Id, T.Column5 AS ColumnId, CAST('<X>' + REPLACE(T.Column5,' ','</X><X>') + '</X>' as XML) AS FilterColumn FROM  @Tbl T UNION ALL
    SELECT T.Id, T.Column6 AS ColumnId, CAST('<X>' + REPLACE(T.Column6,' ','</X><X>') + '</X>' as XML) AS FilterColumn FROM  @Tbl T 
), CTE2
AS 
(
    SELECT 
        A.*,
        B.SplitData
    FROM
        CTE1 A CROSS APPLY
        (SELECT fdata.D.value('.','varchar(50)') AS SplitData FROM A.FilterColumn.nodes('X') as fdata(D)) B
)

SELECT
    T.Id ,
    (SELECT COUNT(DISTINCT C.SplitData) FROM CTE2 C WHERE C.Id = T.Id AND C.ColumnId IN (T.Column3)) Column3OfDistinct,
    (SELECT COUNT(DISTINCT C.SplitData) FROM CTE2 C WHERE C.Id = T.Id AND C.ColumnId IN (T.Column3, T.Column4)) Column4OfDistinct,
    (SELECT COUNT(DISTINCT C.SplitData) FROM CTE2 C WHERE C.Id = T.Id AND C.ColumnId IN (T.Column3, T.Column4, T.Column5)) Column5OfDistinct,
    (SELECT COUNT(DISTINCT C.SplitData) FROM CTE2 C WHERE C.Id = T.Id AND C.ColumnId IN (T.Column3, T.Column4, T.Column5, T.Column6)) Column6OfDistinct    
FROM
    @Tbl T

Result:

Id         Column3OfDistinct Column4OfDistinct Column5OfDistinct Column6OfDistinct
---------- ----------------- ----------------- ----------------- -----------------
items      3                 4                 5                 5

Answer 4

This should help you:

    select
        id,
        count(items)
    from table_name
    group by id