Python - 检查字符串中是否有两个单词

Question

I would like to check whether 2 words "car" and "motorbike" are in each element of an array in Python. I know how to check for one word with in but have no idea how to do with 2 words. Really appreciate any help

Answer 1

Two word solution:

for string in array:
    if 'car' in string and 'motorbike' in string.split():
        print("Car and motorbike are in string")

n-word solution to check if all words in test_words are in string :

test_words = ['car', 'motorbike']
contains_all = True

for string in array:
    for test_word in test_words:
        if test_word not in string.split()::
            contains_all = False
            break
    if not contains_all:
        break

if contains_all:
    print("All words in each string")
else:
    print("Not all words in each string")

Answer 2

Use an auxiliar boolean.

car=False
 motorbike=False
 for elem in array:

        if "car" in elem:
            car=True
        if "motorbike" in elem:
            motorbike=True
        if car and motorbike:
            break

EDIT: I just read "in each element". Just use AND.

Answer 3

I think a simple solution is this:

all(map(lambda w: w in text, ('car', 'motorbike')))

But there might be a problem with this, depending on how picky you need the comparison to be:

>>> text = 'Can we buy motorbikes in carshops?'
>>> all(map(lambda w: w in text, ('car', 'motorbike')))
True

The words 'car' and 'motorbike' are NOT in the text , and this still says True . You might need a full match in words. I would do this:

>>> words = ('car', 'motorbike')
>>> text = 'Can we buy motorbikes in carshops?'
>>> set(words).issubset(text.split())
False
>>> text = 'a car and a motorbike'
>>> set(words).issubset(text.split())
True

And now it works!

Answer 4

I would use the all function:

wanted_values = ("car", "motorbike")
all(vehicle in text for text in wanted_values)

So if we have a list of strings:

l = ['some car and motorbike',
     'a motorbike by a car',
     'the car was followed by a motorbike']

lines_with_vehicles = [text for text in l
                       if all(vehicle in text for text in wanted_values)]

With regex you could do:

# no particular order
car_and_motorbike_pattern = re.compile(r'(car.*motorbike|motorbike.*car)')
all(car_and_motorbike_pattern.search(text) for text in list_of_expressions)

# This works too
car_or_motorbike_pattern = re.compile(r'(car|motorbike)')
get_vehicles = car_or_motorbike_pattern.findall
all(len(set(get_vehicles(text))) == 2 for text in list_of_expressions)

Answer 5

This link worked for me: It offers 3 solutions. Two methods use list comprehensions and the third one uses map + lambda functions.

---

I think there is not an easy and pythonic way to do that. You need to use an ugly logic like the next:

image_file_name = 'man_in_car.jpg'
if 'car' in image_file_name and 'man' in image_file_name:
    print('"car" and "man" were found in the image_file_name')

That would work for two words, but if you need to check many words, then better use the code in the link above

---

I would like to be able to do something like:

if 'car' and 'man' in image_file_name:
    print('"car" and "man" were found in the image_file_name')

Or:

if any(['car','man'] in image_file_name):
    print('"car" and "man" were found in the image_file_name')

But these 2 last pieces of code don't work in python (yet).

Answer 6

Use this function to check for two or more keywords in a sentence with 'and' or 'or' operators.

def check_words(operator = 'and', words = ['car', 'bike'],
                sentence = 'I own a car but not a bike'):

    if operator == 'and':
        word_present = True
        for w in words:
            if w in sentence:
                word_present = True
            else:
                word_present = False
        return word_present

    elif operator == 'or':
        for w in words:
            if w in sentence:
                return True
            else:
                return False
        

check_words(operator = 'and', words = ['car', 'bike'],
            sentence = 'I own a car but not a bike')