如何在Location和Font属性的设计时复制行为（举个例子）

Question

I want to set a property which contains other properties inside (Like font or Location Properties), I've done the following:

class Example:DataGridView
{
    private PlusProperties X;

    public Example()
    {
        X = new PlusProperties();
        AdditionalProperties = X;

    }

    [ComVisibleAttribute(true)]
    [System.ComponentModel.Browsable(true), System.ComponentModel.EditorBrowsable(System.ComponentModel.EditorBrowsableState.Always)]
    [System.ComponentModel.DesignerSerializationVisibility(System.ComponentModel.DesignerSerializationVisibility.Content)]
    public PlusProperties AdditionalProperties
    {
        get { return X; }
        set
        {
            X = value;
        }
    }
}

public class PlusProperties
{
    private Color Pcolor = Color.DimGray;
    private Color Ccolor = Color.DimGray;

    public PlusProperties()
    {

    }

    [System.ComponentModel.Browsable(true), System.ComponentModel.EditorBrowsable(System.ComponentModel.EditorBrowsableState.Always)]
    public Color ParentColor
    {
        get { return Pcolor; }
        set
        {
            if (value != Pcolor)
            {
                Pcolor = value;
            }
        }
    }

    [System.ComponentModel.Browsable(true), System.ComponentModel.EditorBrowsable(System.ComponentModel.EditorBrowsableState.Always)]
    public Color ChildColor
    {
        get { return Ccolor; }
        set
        {
            if (value != Ccolor)
            {
                Ccolor = value;
            }
        }
    }

}

How can achieve the same behavior on design time (I mean show the properties of the class)?

Thanks in advance for your help.

Answer 1

You'll want to create a class that inherits ExpandableObjectConverter and add a TypeConverter attribute to your class that uses it. See the following example here: https://msdn.microsoft.com/en-us/library/system.componentmodel.expandableobjectconverter(v=vs.110).aspx