使用基于行分隔符的 grep 内容提取文件内容

Question

I'm trying to extract just the file information using either grep, awk or any linux command

Have: File

Getting Table 'TABLEA'
GET TABLE TABLEA
(value(1)
)
/

Getting Table 'TABLEB'
GET TABLE TABLEB
(value(1) 
,other value(2)
)
/

WANT

An output to contain the following

Getting Table 'TABLEA'
GET TABLE TABLEA
(value(1)
)
/

Answer 1

That would work:

grep -A 4 "^Getting Table 'TABLEA'"

It will get the pattern at the start of the line, print it, and continue printing 4 lines afterwards( -A 4 option)