MySQL使用不同的WHERE子句进行多次计数并查看结果

Question

I am trying to get from my orders table: the number of orders each customer has placed within a week, then do another count for the next week, then again, and again, etc.

I am using COUNT but it keeps bringing back an empty result.

Here is my query.

SELECT `uid`, (SELECT COUNT(`uid`) FROM `orders` WHERE `order_timestamp` > '1476707688' and `order_timestamp` < '1476189288') as 'number1',
       (SELECT COUNT(`uid`) FROM `orders` WHERE `order_timestamp` > '1476189288' and `order_timestamp` < '1475584488') as 'number2',
       (SELECT COUNT(`uid`) FROM `orders` WHERE `order_timestamp` > '1475584488' and `order_timestamp` < '1474979688') as 'number3'
FROM `orders` ORDER BY `uid` ASC

The result looks like this:

I know that there are multiple orders in a week from multiple customers.

How do you do that query? A query that will bring back the number of orders a customer has made in that time period?

Cheers,

Answer 1

Just use conditional aggregation:

SELECT `uid`,
       SUM(`order_timestamp` > '1476707688' and `order_timestamp` < '1476189288') as number1,
       SUM(`order_timestamp` > '1476189288' and `order_timestamp` < '1475584488') as number2,
       SUM(`order_timestamp` > '1475584488' and `order_timestamp` < '1474979688') as number3
FROM `orders`
GROUP BY `uid` ASC;

Note: this aggregates by uid , so there will be one row per uid rather than per order. That seems like the sensible thing to do.

Answer 2

Can you please try as follow?

SELECT * FROM {table} WHERE date > DATE_SUB(NOW(), INTERVAL 1 DAY) ORDER BY uid DESC;        
SELECT * FROM {table}WHERE date > DATE_SUB(NOW(), INTERVAL 1 WEEK) ORDER BY uid DESC;
SELECT * FROM {table}WHERE date > DATE_SUB(NOW(), INTERVAL 1 MONTH) ORDER BY uid DESC;