[英]Got problems with replacing xml nodes within text
I'm working on XML-to-XML transformation (Windows 10, Oxygen XML Editor) and got this task: replace <xref id="id1">text</xref>
with id1
. 我工作的XML到XML的转换(视窗10,氧XML编辑器),并得到了这个任务:更换
<xref id="id1">text</xref>
与id1
。
I've done some work but can't get why doesn't scenario replace all xref-s in parentheses. 我已经做了一些工作,但无法理解为什么方案不替换括号中的所有外部参照。 Any ideas?
有任何想法吗?
And just in case if somebody know how to remove parentheses outside of xref-s, please tell. 并且以防万一有人知道如何删除外部参照之外的括号,请告诉。 I was trying
concat('(',$temp,')')
but it also skips parenteses and concat('(',$temp,';')
even doesn't work. 我正在尝试
concat('(',$temp,')')
但它也跳过了括号,而concat('(',$temp,';')
甚至不起作用。
Here the example (I keep punctuation just in case): 这是示例 (我保留标点符号以防万一):
<section>
<somenode>Lorem ipsum</somenode>
<p>Lorem ipsum (<xref id="id1">TEXT1, 2014</xref>) dolor.</p>
<p>Lorem ipsum (<xref id="id5">TEXT5., 2016</xref>) dolor.</p>
<p>Lorem ipsum (<xref id="id6">TEXT6., 2004</xref>; <xref id="id7">TEXT7., 2014</xref>; <xref id="id8">TEXT8., 2012</xref>), dolor.</p>
<p>Lorem ipsum (<xref id="id6">TEXT6., 2004</xref>; <xref id="id7">TEXT7., 2014</xref>; <xref id="id8">TEXT8., 2012</xref>), dolor.</p>
...
</section>
...
Here the result : 结果如下:
<section>
<somenode>Lorem ipsum</somenode>
<p>Lorem ipsum (id1) dolor.</p>
<p>Lorem ipsum (id5) dolor.</p>
<p>Lorem ipsum (id6; TEXT7., 2014; TEXT8., 2012), dolor.</p>
<p>Lorem ipsum (TEXT6., 2004; id7; TEXT8., 2012), dolor.</p>
...
</section>
...
I expect : 我希望 :
<section>
<somenode>Lorem ipsum</somenode>
<p>Lorem ipsum (id1) dolor.</p>
<p>Lorem ipsum (id5) dolor.</p>
<p>Lorem ipsum (id6; id7; id8), dolor.</p>
<p>Lorem ipsum (id6; id7; id8), dolor.</p>
...
</section>
...
and Here the scenario : 这里是场景 :
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xs="http://www.w3.org/2001/XMLSchema" exclude-result-prefixes="xs" version="2.0">
<xsl:output method="xml" encoding="UTF-8"/>
<xsl:template name="xrefs">
<xsl:for-each select="section">
<xsl:for-each select="p">
<xsl:variable name="tempP">
<xsl:value-of select="."/>
</xsl:variable>
<xsl:for-each select="xref">
<xsl:variable name="temp">
<xsl:value-of select="."/>
</xsl:variable>
<xsl:value-of select="replace($tempP,$temp,./@id)"/>
</xsl:for-each>
</xsl:for-each>
</xsl:for-each>
</xsl:template>
<xsl:template match="/">
<xsl:call-template name="xrefs"/>
</xsl:template>
got this task: replace
<xref id="id1">text</xref>
withid1
.得到了以下任务:将
<xref id="id1">text</xref>
替换为id1
。
That could be done easily by: 可以通过以下方法轻松完成:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:strip-space elements="*"/>
<!-- identity transform -->
<xsl:template match="@*|node()">
<xsl:copy>
<xsl:apply-templates select="@*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="xref">
<xsl:value-of select="@id"/>
</xsl:template>
</xsl:stylesheet>
Applies to the following well-formed (!) input example: 适用于以下格式正确的(!)输入示例:
XML XML格式
<section>
<somenode>Lorem ipsum</somenode>
<p>Lorem ipsum (<xref id="id1">TEXT1, 2014</xref>) dolor.</p>
<p>Lorem ipsum (<xref id="id5">TEXT5., 2016</xref>) dolor.</p>
<p>Lorem ipsum (<xref id="id6">TEXT6., 2004</xref>; <xref id="id7">TEXT7., 2014</xref>; <xref id="id8">TEXT8., 2012</xref>), dolor.</p>
<p>Lorem ipsum (<xref id="id6">TEXT6., 2004</xref>; <xref id="id7">TEXT7., 2014</xref>; <xref id="id8">TEXT8., 2012</xref>), dolor.</p>
...
</section>
the result will be: 结果将是:
<?xml version="1.0" encoding="UTF-8"?>
<section>
<somenode>Lorem ipsum</somenode>
<p>Lorem ipsum (id1) dolor.</p>
<p>Lorem ipsum (id5) dolor.</p>
<p>Lorem ipsum (id6; id7; id8), dolor.</p>
<p>Lorem ipsum (id6; id7; id8), dolor.</p>
...
</section>
And just in case if somebody know how to remove parentheses outside of xref-s, please tell.
并且以防万一有人知道如何删除外部参照之外的括号,请告诉。
That could be achieved by adding these two templates (requires XSLT 2.0): 可以通过添加以下两个模板来实现(需要XSLT 2.0):
<xsl:template match="text()[following-sibling::*[self::xref]][ends-with(., '(')]">
<xsl:value-of select="substring(., 1, string-length() - 1) "/>
</xsl:template>
<xsl:template match="text()[preceding-sibling::*[self::xref]][starts-with(., ')')]">
<xsl:value-of select="substring(., 2) "/>
</xsl:template>
Then the result will be: 那么结果将是:
<?xml version="1.0" encoding="UTF-8"?>
<section>
<somenode>Lorem ipsum</somenode>
<p>Lorem ipsum id1 dolor.</p>
<p>Lorem ipsum id5 dolor.</p>
<p>Lorem ipsum id6; id7; id8, dolor.</p>
<p>Lorem ipsum id6; id7; id8, dolor.</p>
...
</section>
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