用键数组过滤对象数组[反]

Question

I have this following keys array:

var keys = [{userId: "333"}, {userId: "334"}]

And this objects array:

var users = [
{id: "333", firstName: "", lastName: "", idCard: "", birthDate: ""},
{id: "334", firstName: "", lastName: "", idCard: "", birthDate: ""},
{id: "335", firstName: "", lastName: "", idCard: "", birthDate: ""},
{id: "336", firstName: "", lastName: "", idCard: "", birthDate: ""}
]

I need to change my users Array by filter it with my keys Array [inverse result].

Cant figure it out, get all the answers! (js, jquery, angular)

Anyone?

Answer 1

You can use filter() and find() .

 var users = [ {id: "333", firstName: "", lastName: "", idCard: "", birthDate: ""}, {id: "334", firstName: "", lastName: "", idCard: "", birthDate: ""}, {id: "335", firstName: "", lastName: "", idCard: "", birthDate: ""}, {id: "336", firstName: "", lastName: "", idCard: "", birthDate: ""} ] var keys = [{userId: "333"}, {userId: "334"}] var result = users.filter(function(o) { return !keys.find(function(e) { return e.userId == o.id }) }) console.log(result) 

Answer 2

You can have an array of id s and then you can just check for availability in this list

 var users = [ {id: "333", firstName: "", lastName: "", idCard: "", birthDate: ""}, {id: "334", firstName: "", lastName: "", idCard: "", birthDate: ""}, {id: "335", firstName: "", lastName: "", idCard: "", birthDate: ""}, {id: "336", firstName: "", lastName: "", idCard: "", birthDate: ""} ] var keys = [{userId: "333"}, {userId: "334"}] var idList = keys.map(function(x){ return x.userId}); var r = users.filter(function(x){ return idList.indexOf(x.id) < 0 }) console.log(r) 

Answer 3

You could use a hash table for filtering.

 var keys = [{ userId: "333" }, { userId: "334" }], users = [{ id: "333", firstName: "", lastName: "", idCard: "", birthDate: "" }, { id: "334", firstName: "", lastName: "", idCard: "", birthDate: "" }, { id: "335", firstName: "", lastName: "", idCard: "", birthDate: "" }, { id: "336", firstName: "", lastName: "", idCard: "", birthDate: "" }], filtered = users.filter(function (a) { return !this[a.id]; }, keys.reduce(function (r, a) { r[a.userId] = true; return r; }, Object.create(null))); console.log(filtered); 

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