Javascript：用带有正则表达式的'b'替换字符串中'a'的所有出现

Question

I have a string like 'abbba' and want to replace every 'b' in that string that has a whitespace before and after the character with a different character. How could I do that with a regex? My idea was this:

'x a y a x'.replace(new RegExp(' a ', 'g'), ' b '); // is: x b y b x, should: x b y b x (correct)
'x a a a x'.replace(new RegExp(' a ', 'g'), ' b '); // is: x b a b x, should: x b b b x (wrong)
'x aa x'.replace(new RegExp(' a ', 'g'), ' b '); // is: x aa x, should: x aa x (correct)

But that regex is only working if there is not more than 1 occurence of the character next to another occurence of the character. How could I write the regex to get the right behaviour?

Answer 1

Use a lookahead after " a" to match overlapping substrings:

/ a(?= )/g

Or, to match any whitespace, replace spaces with \\s .

The lookahead , being a zero-width assertion , does not consume the text, so the space after " a" will be available for the next match (the first space in the pattern is part of the consuming pattern).

See the regex demo

 var regex = / a(?= )/g; var strs = ['xaya x', 'xaaa x', 'x aa x']; for (var str of strs) { console.log(str,' => ', str.replace(regex, " b")); } 

Answer 2

As your matches are overlapping, you can use zero width assertion ie a positive lookahead based regex:

str = str.replace(/( )a(?= )/g, "\1b");

RegEx Demo

• ( )a will match a space before a and capture it in group #1 followed by a
• (?= ) will assert presence of a space after a but won't consume it in the match.

Answer 3

You can use RegExp with g flag with the replace method. Try this

var mystring = "this is a a a a a a test"
mystring.replace(/ a /g , "b");