[英]generate and stream output of a command over HTTP on demand
I'm doing a little Swiss Army Linuxing right now. 我现在正在做一些瑞士军Linuxing。 I've run into a situation where I want to run a command, then pipe it into an HTTP server, which serves just that stream. 我遇到了要运行命令,然后将其通过管道传送到仅用于该流的HTTP服务器的情况。 Here's the whole scenario: 这是整个场景:
Start the server with a line like 用以下行启动服务器
$ httpondemand parecord
Server does not start parecord right away. 服务器无法立即启动parecord。
HTTP client connects. HTTP客户端连接。
$ wget -O - http://server/ | mpv -
I CAN HAZ "/" ? 我可以危害“ /”吗?
I am about to write the tool myself, but I thought I'd ask if there were anything already capable of this. 我将要自己编写该工具,但我想问一下是否已经有任何功能可以使用。
I couldn't find a tool that could do this, so I did end up writing one, which for reasons beyond the scope of this document, was named todd
. 我找不到能做到这一点的工具,因此我最终写了一个工具,由于超出了本文档的范围,该工具被命名为todd
。 I'd still rather use something that already exists, so this is not my ideal solution. 我还是想使用已经存在的东西,所以这不是我理想的解决方案。
#!/usr/bin/env python
from socketserver import TCPServer
from http.server import BaseHTTPRequestHandler
import subprocess as sp
from sys import *
class ToddHandler(BaseHTTPRequestHandler):
def do_GET(self):
self.send_response(200)
self.end_headers()
# Do not start the command until after a connection has been made.
p = sp.Popen(argv[1:], stdout=sp.PIPE)
while True:
data = p.stdout.read(1024)
if len(data) == 0:
break
try:
self.wfile.write(data)
except BrokenPipeError:
break
except ConnectionResetError:
break
p.stdout.close()
p.wait() # Kill the zombie.
if len(argv) == 1:
stderr.write('usage: todd command [arg1 arg2 ...]\n')
# Create the server.
server = TCPServer(('', 10000), ToddHandler)
# Activate the server; this will keep running until you
# interrupt the program with Ctrl-C
server.serve_forever()
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