Python-返回列表枚举的整数值

Question

Is there a cleaner way to get an integer value of the position of a list item in this code:

a = ['m', 'rt', 'paaq', 'panc']
loc = [i for i, x in enumerate(a) if x == 'rt']
loc_str = str(loc).strip('[]')
loc_int = int(loc_str)
id_list = a[loc_int + 1:]
print id_list

Returns all items after 'rt' as a list ['paaq', 'panc']

Answer 1

Yes, use list.index() .

a = ['m', 'rt', 'paaq', 'panc']
id_list = a[a.index('rt')+1:]
assert id_list == ['paaq', 'panc']

Or, to minimally change your program:

a = ['m', 'rt', 'paaq', 'panc']
loc_int = a.index('rt')
id_list = a[loc_int + 1:]
print id_list

References:

• https://docs.python.org/2/library/stdtypes.html#sequence-types-str-unicode-list-tuple-bytearray-buffer-xrange
• https://docs.python.org/2/tutorial/datastructures.html#more-on-lists

Answer 2

a[a.index('rt') + 1:]

What this is doing is slicing the array, starting at where a.index('rt') . not specifying an end :] means we want until the end of the list.