[英]Sort subdocument using mongoose (MongoDB)
I am trying to do something very simple but an new to MongoDB! 我正在尝试做一些非常简单的事情,但却是MongoDB的新功能! I have a document called Device and a sub-document called Movement.
我有一个名为Device的文档和一个名为Movement的子文档。 I want to get the last two movement sub-documents out of Device ordered by
last_seen
(a date). 我想从
last_seen
(日期)排序的设备中获取最后两个移动子文档。 Here is what I have along with the error I am getting: 这是我所遇到的错误:
Device.findOne({device_id: "1234"}, {movements: { $sort: {last_seen: -1}, $slice: 2 }}, function(err, device){
...
});
The Error: 错误:
MongoError: >1 field in obj: { $sort: { last_seen: -1 }, $slice: 2 }
You can use aggregate : 您可以使用聚合 :
Device.aggregate(
{ $match: { device_id: "1234"}}, // query documents (can return more than one element)
{ $unwind: '$movements'}, //deconstruct the documents
{ $sort: { '$movements.last_seen': -1}},
{ $limit: 2 },
{ $group: { _id: '$device_id', movements: { $push: '$movements }}} //reconstruct the documents
function(err, devices){
//returns an array, probably with one elements depending on `$match` query
});
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