快速结构作为功能参数

Question

I have a struct/model that I store some JSON data to fill my tableview:

import SwiftyJSON

struct MyData {

    let valOne: Int
    let valTwo: String
    let valThree: Int

    init(json: JSON) {
        valOne = json["some_data"].intValue
        valTwo = json["auc_data"].stringValue
        valThree = json["auc_data"].intValue
    }
}

Then in my tableview I have a custom cell class that I use when I write out my data:

let data = MyData[indexPath.row]

let cell = tableView.dequeueReusableCell(withIdentifier: "myCell") as! CustomTableViewCell

cell.configureCellWithData(data)

What I want to do is to pass the struct as a parameter to the configureCellWithData() but I am not sure how to declare it.

Instead of doing something like:

func configureCellWithData(dataOne: Int, dataTwo: String, dataThree: Int) {

}

then

configureCellWithData(data.valOne,data.valTwo,data.valThree)

I dont want to have many parameters instead I want to send the struct right away

Answer 1

Try this.

func configureCellWith(data: MyData) {
    // Do stuff here
}