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WCF反序列化JSON字符串

[英]WCF Deserialize JSON String

I had edited my question : 我已经编辑了我的问题:

How can i deserialize the JSON string shows below : 我如何反序列化JSON字符串,如下所示:

"{\"acctId\": \"Test10001\",\"amount\": 200,\"currency\": \"USD\",\"Code\": \"Test\",\"serialNo\": \"1234566789asdsad0\"}"

Please give suggestion how can I get the data by using this method or any other recommended method. 请提出建议,如何使用此方法或任何其他推荐方法获取数据。

Suggesting you to use StreamWriter as below. 建议您如下使用StreamWriter Use this function and pass your string and return a the Stream which will give you the desired JSON Content 使用此函数并传递您的字符串并返回一个Stream,它将为您提供所需的JSON内容

public static Stream GenerateStreamFromString(string s)
{
         MemoryStream stream = new MemoryStream();
         StreamWriter writer = new StreamWriter(stream);
         writer.Write(s);
         writer.Flush();
         stream.Position = 0;
         return stream;
}

The payload of your POST request seems to be in JSON format, so you should use a JSON parsing library to parse it, such as Json.NET . POST请求的有效负载似乎是JSON格式,因此您应该使用JSON解析库来解析它,例如Json.NET Then you would write something like: 然后,您将编写如下内容:

JsonConvert.DeserializeObject<YourRequestObject>(res)

you can read Json string like this 您可以像这样读取Json字符串

dynamic stuff = JObject.Parse(res.ToString());

        string acctId= stuff.acctId;

But the response string you are parsing should be json formatted. 但是您要解析的响应字符串应为json格式。

I think below code should serve your purpose: 我认为下面的代码应达到您的目的:

    public class DeserializedData
    {
        public string acctId { get; set; }
        public string amount { get; set; }
        public string currency { get; set; }
        public string Code { get; set; }
        public string serialNo { get; set; }
    }    

StreamReader reader = new StreamReader(streamdata);
string res = reader.ReadToEnd();

Use third party dlls like Json.NET or Restsharp: 使用第三方dll(例如Json.NET或Restsharp):

1.) Using Json.Net Json.NET 1.)使用Json.Net Json.NET

var result = JsonConvert.DeserializeObject<DeserializedData>(res);

2.) Using Restsharp Restsharp 2.)使用Restsharp Restsharp

var jsonDeserializer = new RestSharp.Deserializers.JsonDeserializer();
var response = jsonDeserializer.Deserialize<DeserializedData>(res);

Let me know if it doesn't work for you. 让我知道这是否对您不起作用。

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