Python os.listdir（）表现异常，需要一些解释

Question

I am using python, with Anaconda on PyCharm IDE (windows 10), and using virtual environment. This is my code in question,

print('# File...')
print(os.listdir("../MyData/Data/"))

When I run the code in console (right-click and then "Execute Section in Console") it works perfectly. However, as I run the entire code (from the green button) it says, FileNotFoundError: [WinError 3] The system cannot find the path specified: '../MyData/Data/'

Can someone please explain why is it happening, and a possible direction? Thank you.

Answer 1

Be carefull, Windows usually have "\\" in the address. This is very simple but could be a big problem. Since "\\" is used as a escape, you will have to use "\\\\" . Try this test and see it the address is correct:

import os
print(os.getcwd())

It will print your current work directory

Answer 2

您应使用完整路径，如下所示：

os.listdir ("C:\Users\YourUsername\Full\Path")

Answer 3

All programs have a working directory decided by whatever code started it. When you right click and run in console, the console, as part of its initialization process, specifically sets current working directory to your home directory. When you run in the gui what happens depends on the window manager that starts the program. I think Microsoft Windows likes to set CWD to the directory of the executable, but I'm not sure.

The way to fix it is to manually set the current directory when your program starts.

import os
os.chdir(os.path.expanduser('~'))

You can do this in the gui and console cases. After this code runs, relative paths will be relative to your home directory.