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耶拿推理和规则语法

[英]Jena Reasoning and Rule Syntax

I have a questions regarding to the Jena API. 我对Jena API有疑问。

I wrote some rules that are working perfectly but with one thing I still have a problem. 我写了一些很好的规则,但是一件事我仍然有一个问题。 I hope you can help me with it. 希望您能帮助我。

Comparison of two integer 两个整数的比较

In my rules I need a comparison like "GreaterThan". 在我的规则中,我需要像“ GreaterThan”这样的比较。 I searched long for it but not a single version worked. 我搜索了很长时间,但没有一个版本可以工作。 I tried GreaterThan(?x, ?y) as part of the rule as well as the namespace swrlb: <http://www.w3.org/2003/11/swrlb#> with its function swrlb:GreaterEqual , but both did not worked. 我尝试了GreaterThan(?x, ?y)作为规则的一部分,还swrlb:了命名空间swrlb: <http://www.w3.org/2003/11/swrlb#>及其功能swrlb:GreaterEqual ,但是两者都做了没有用。

The rule looks like follows: 该规则如下所示:

[r0: (?x es:has_intensity ?I), GreaterThan(?I, 2) -> (?x es:test "true")] 

or my alternative: 或者我的选择:

[r0: (?x es:has_intensity ?I), (?I swrlb:Greater 2) -> (?x es:test "true")]

The main issue that you are probably experiencing is that you are not using a known builtin. 您可能遇到的主要问题是您没有使用已知的内置函数。 The builtins are case-sensitive. 内建函数区分大小写。

As seen in Jena's owl-fb.rules , the builtin that you intend to use is greaterThan , not GreaterThan . 正如在耶拿看到owl-fb.rules ,你打算使用内置的是greaterThan ,不GreaterThan An example of a rule using the builtin (from owl-fb.rules ) follows: 使用内置规则的示例(来自owl-fb.rules )如下:

[validationMaxN: (?v rb:validation on()), (?C rdfs:subClassOf max(?P, ?N)) greaterThan(?N, 1) (?P rdf:type owl:DatatypeProperty) ->
    [max2b: (?X rb:violation error('too many values', 'Too many values on max-N property (prop, class)', ?P, ?C))
          <- (?X rdf:type ?C), countLiteralValues(?X, ?P, ?M), lessThan(?N, ?M)  ] ]

Editing your rule yields: 编辑规则将产生:

[r0: (?x es:has_intensity ?I), greaterThan(?I, 2) -> (?x es:test "true")] 

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