如何在PostgreSQL中使用SQL记录分钟

Question

I have a result using SQL inside a function

select a[2] as hour, a[3] minutes from ( select regexp_split_to_array('for  7h 18m', ' ') ) as dt(a);

and i got result as

hour    minutes
7h       18m

I want to get

minutes
 438

Answer 1

该文档有一个使用摘录和纪元的示例 。

SELECT EXTRACT(EPOCH FROM '2h 18m'::INTERVAL)/60;

Answer 2

One option here is to remove the h from the hours string, multiply by 60 to get minutes, then add this quantity to the minutes field, with the m removed. Try this query:

select regexp_replace(a[2], '[h\s]', '')::integer * 60 +
       regexp_replace(a[3], '[m\s]', '')::integer as minutes
from
(
    select regexp_split_to_array('for  7h 18m', ' ')
) as dt(a);