Python：使用列表推导将列表切成列表列表

Question

I have a simple list like this:

mylist=[0,1,2,3,4,5,6,7,8,9]

which I want to slice creating a list of lists. The intended outcome is:

sliced=[[0],[0,1],[0,1,2],[0,1,2,3],...]

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1. First attempt: sliced=[mylist[i:i+n] for i in range(0, len(mylist), n)]

   wrong result: sliced=[[0, 1, 2, 3, 4, 5, 6, 7, 8, 9]]

---

2. Second attempt: sliced=[[mylist[l]] for l in range(0,10,1)]

   wrong result: sliced=[[0], [1], [2], [3], [4], [5], [6], [7], [8], [9]]

---

How should I handle this?

Answer 1

Like this?

>>> mylist = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
>>> sliced = [mylist[0:i] for i in range(1, len(mylist) + 1)]
>>> sliced
[[0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 3, 4, 5], [0, 1, 2, 3, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6, 7], [0, 1, 2, 3, 4, 5, 6, 7, 8], [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]]

Further reading: Explain Python's slice notation