[英]creating 3rd party API with PHP and JSON
I have an API for my website, I want to use it for mobile applications. 我的网站有一个API,我想将其用于移动应用程序。 but the problem is these APIs provide a lot of data that is not needed, so I wanted to make a third-party API that filter data obtained from the first API.
但是问题是这些API提供了很多不需要的数据,因此我想制作一个第三方API,以过滤从第一个API获得的数据。
as an example, I want to filter article list data obtained from the first API, I've done is the following: 例如,我要过滤从第一个API获得的文章列表数据,我做了以下工作:
<?php
header('Content-type: application/json');
if (isset($_GET['kat'])) {
$url = $_GET['kat'];
} else {
$url = null;
}
$app_list = file_get_contents('http://localhost/api/articles/lists');
$app_list = json_decode($app_list, true);
foreach ($app_list as $app) {
$id = $app['id'];
$uid = $app['user_id'];
$cat = $app['category'];
$tgl = $app['created_date'];
$img = $app['image'];
$posttipe = $app['post_user_type'];
$komen = $app['count_comment'];
$likes = $app['count_likes'];
$c = substr($app['content'], 0, 100);
$content= $c . "...";
if ($cat == $url || !$url) {
$list = array("id" => $id, "user_id" => $uid, "category" => $cat, "image" => $img, "post_user_type" => $posttipe, "count_comment" => $komen, "count_likes" => $likes, "created_date" => $tgl, "content" => $content);
}
}
echo json_encode($list);
?>
that so my problem is, that the API I made do not show all the list of articles obtained from API first. 所以我的问题是,我制作的API并未首先显示从API获得的所有文章列表。
i use $_GET['kat'];
我用
$_GET['kat'];
to filter articles categories 筛选文章类别
what should I edit in my script? 我应该在脚本中编辑什么?
You are loading $list
in a loop so 您正在循环加载
$list
,因此
$list = array("id" => $id, .....);
is over writing $list
each time round the loop! 每次循环都写
$list
了!
Change this line to 将此行更改为
$list[] = array("id" => $id, .....);
And now you will be creating an array of arrays, containing all the results of your looped data. 现在,您将创建一个数组数组,其中包含循环数据的所有结果。
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