[英]JS/PHP - auto-populate select fields based on previous selection
SO I have 3 select fields and I would like to populate the #2 and #3 based on the selected value in #1. 所以我有3个选择字段,我想根据#1中的选定值填充#2和#3。
JS is picking up on the field change in #1, submits it successfully to my PHP script, but there I receive an "Array to string conversion" error when inserting the $_POST['problem'] variable into my query to get the related results. JS正在获取#1中的字段更改,已将其成功提交到我的PHP脚本,但是在向查询中插入$ _POST ['problem']变量以获取相关内容时,我收到“数组到字符串转换”错误结果。
I did try json_encode and made sure the original selected value in the first select field (select id="problem") is an array, hence do not understand where the conversion error comes from. 我确实尝试了json_encode并确保在第一个选择字段(选择id =“ problem”)中原始选择的值是一个数组,因此不了解转换错误的来源。
ERROR: 错误:
<b>Notice</b>: Array to string conversion in <b>Z:\xampp\htdocs\qcisource\ihg\ajax.php</b> on line <b>17</b><br />
{"current_field":null,"field_count":null,"lengths":null,"num_rows":null,"type":null}
Any suggestions? 有什么建议么?
HTML 的HTML
<p>Problem Experienced</p>
<!-- Problem -->
<div class="input-group">
<span class="input-group-addon"><i class="fa fa-warning"></i></span>
<select id="problem" name="problem" class="form-control select2" multiple="multiple" data-placeholder="Select a Problem">
<option value=""> </option>
<?php
// define query
$sql = "SELECT Issue, Description FROM qci_problems_index_new ORDER BY Issue";
// query
$result = $mysqli->query($sql) or die('<p>Query to get Issue from qci_problems_index_new table failed: ' . mysql_error() . '</p>');
while ($row = $result->fetch_array(MYSQLI_ASSOC)) {
$problem = $row['Issue'];
$desc = $row['Description'];
echo "<option value=\"$problem\" data-desc=\"$desc\">" . $problem . "</option>\n";
}
$result->free();
?>
</select>
</div>
<p>Problem Category</p>
<!-- Problem Category -->
<div class="input-group">
<span class="input-group-addon"><i class="fa fa-warning"></i></span>
<select id="problem_category" name="problem_category" class="form-control select2" multiple="multiple" data-placeholder="Select a Problem Category">
<option value=""> </option>
<?php
// define basic query
$sql = "SELECT DISTINCT Category FROM qci_problems_index_new ORDER BY Category";
// query
$result = $mysqli->query($sql) or die('<p>Query to get Category data from qci_problems_index_new table failed: ' . mysql_error() . '</p>');
while ($row = $result->fetch_array(MYSQLI_ASSOC)) {
$category = $row["Category"];
echo "<option value=\"$category\">" . $category . "</option>\n";
}
$result->free();
?>
</select>
</div>
<p>Department Responsible</p>
<!-- Department Responsible -->
<div class="input-group">
<span class="input-group-addon"><i class="fa fa-bars"></i></span>
<select id="department" name="department" class="form-control select2" multiple="multiple" data-placeholder="Select a Department">
<option value=""> </option>
<?php
// define basic query
$sql = "SELECT DISTINCT Department_Responsible FROM qci_problems_index_new ORDER BY Department_Responsible";
// query
$result = $mysqli->query($sql) or die('<p>Query to get department_responsible from qci_problems_index_new table failed: ' . mysql_error() . '</p>');
while ($row = $result->fetch_array(MYSQLI_ASSOC)) {
$dept = $row["Department_Responsible"];
echo "<option value=\"$dept\">" . $dept . "</option>\n";
}
$result->free();
?>
</select>
</div>
JS JS
<script type="text/javascript" language="javascript">
$(function () {
$('#problem').change(function () {
$.ajax({
type: 'POST',
url: 'ajax.php',
data: {
problem: $(this).val()
},
dataType: 'json',
success: function (data)
{
var Category = data[0];
var Department_Responsible = data[1];
$('#problem_category').val(Category);
$('#department').val(Department_Responsible);
}
});
});
});
</script>
ajax.php ajax.php
<?php
if(isset($_POST['problem'])) {
// Start MySQLi connection
include './plugins/MySQL/connect_db.php';
$db = new mysqli($dbhost,$dbuser,$dbpass,$dbname);
// display error if connection cannot be established
if($db->connect_errno > 0){
die('Unable to connect to database [' . $mysqli->connect_error . ']'); }
// sanitize variables
$problem = $_POST['problem']; //mysqli_real_escape throws error, ignore for now
// run query
$result = $db->query("SELECT Category, Department_Responsible FROM qci_problems_index_new WHERE Issue= '".$problem."'");
// return data as array
$array = mysqli_fetch_array($result);
echo json_encode($result);
}
?>
Fixed it myself... 我自己修复了...
Apart from some minor mistakes with the JavaScript, the main problem was that I am using the Jquery Select2 plugin which doesn't handle AJAX in the same way that regular <select>
fields do. 除了JavaScript的一些小错误外,主要问题是我正在使用Jquery Select2插件,该插件无法以与常规
<select>
字段相同的方式处理AJAX。 I had to manually trigger('change')
on all my fields to get the AJAX value displayed. 我必须在所有字段上手动
trigger('change')
才能显示AJAX值。
Javascript Java脚本
<script type="text/javascript" language="javascript">
$(function () {
$('#problem').change(function () {
$.ajax({
type: 'POST',
url: 'ajax.php',
data: 'problem=' + $(this).val(),
dataType: 'json',
success: function (data)
{
var data0 = data[0];
var data1 = data[1];
$('#problem_category').val(data0);
$('#department').val(data1);
$('#problem_category').trigger('change');
$('#department').trigger('change');
}
});
});
});
</script>
Ajax.php Ajax.php
<?php
error_reporting(E_ALL);
ini_set('display_errors', 1);
if(isset($_POST['problem'])) {
// Start MySQLi connection
include '../../plugins/MySQL/connect_db.php';
$db = new mysqli($dbhost,$dbuser,$dbpass,$dbname);
// display error if connection cannot be established
if($db->connect_errno > 0){
die('Unable to connect to database [' . $db->connect_error . ']'); }
// run query
$sql = "SELECT Category, Department_Responsible FROM qci_problems_index_new WHERE Issue= '".$_POST['problem']."'";
$result = $db->query($sql) or die(mysqli_error());
// return data as array
$array = mysqli_fetch_array($result);
echo json_encode($array);
}
?>
HTML: HTML:
<p>Problem Experienced</p>
<!-- Problem -->
<div class="input-group">
<span class="input-group-addon"><i class="fa fa-warning"></i></span>
<select id="problem" name="problem" class="form-control select2" data-placeholder="Select a Problem" style="width: 100%;">
<option value=""> </option>
<?php
// define query
$sql = "SELECT Issue, Description FROM qci_problems_index_new ORDER BY Issue";
// query
$result = $mysqli->query($sql) or die('<p>Query to get Issue from qci_problems_index_new table failed: ' . mysql_error() . '</p>');
while ($row = $result->fetch_array(MYSQLI_ASSOC)) {
$problem = $row['Issue'];
$desc = $row['Description'];
echo "<option value=\"$problem\" data-desc=\"$desc\">" . $problem . "</option>\n";
}
$result->free();
?>
</select>
</div>
<p class="help-block" width="100%"><div id="output01" name="output01"></div></p>
<hr />
<p>Problem Category</p>
<!-- Problem Category -->
<select id="problem_category" name="problem_category" class="form-control select2" data-placeholder="Select a Problem Category" style="width: 100%;">
<option value=""> </option>
<?php
// define basic query
$sql = "SELECT DISTINCT Category FROM qci_problems_index_new ORDER BY Category";
// query
$result = $mysqli->query($sql) or die('<p>Query to get Category data from qci_problems_index_new table failed: ' . mysql_error() . '</p>');
while ($row = $result->fetch_array(MYSQLI_ASSOC)) {
$category = $row["Category"];
echo "<option value=\"$category\">" . $category . "</option>\n";
}
$result->free();
?>
</select>
<hr />
<p>Department Responsible</p>
<!-- Department Responsible -->
<div class="input-group">
<span class="input-group-addon"><i class="fa fa-bars"></i></span>
<select id="department" name="department" class="form-control select2" data-placeholder="Select a Department" style="width: 100%;">
<option value=""> </option>
<?php
// define basic query
$sql = "SELECT DISTINCT Department_Responsible FROM qci_problems_index_new ORDER BY Department_Responsible";
// query
$result = $mysqli->query($sql) or die('<p>Query to get department_responsible from qci_problems_index_new table failed: ' . mysql_error() . '</p>');
while ($row = $result->fetch_array(MYSQLI_ASSOC)) {
$dept = $row["Department_Responsible"];
echo "<option value=\"$dept\">" . $dept . "</option>\n";
}
$result->free();
?>
</select>
</div>
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