无法使用特定半径的Android在Google地图中找到地点

Question

I want to find places of interest under a specific radius using Android. I am working in this way

 String uri = "geo:"+ 40.007620 + "," + -75.160264 +"&q=child hospitals";
                startActivity(new Intent(android.content.Intent.ACTION_VIEW, Uri.parse(uri)));

But when I run the application, It opens the google maps but does not mark the child hospitals . Any wrong here?

Answer 1

Try this,

Intent intent = new Intent(Intent.ACTION_VIEW,
                Uri.parse("geo:<40.007620>,<-75.160264>?q=<40.007620>,<-75.160264>(child hospitals)"));
        startActivity(intent);

Answer 2

Please check below reference which will guide you to how to pass or format map intent query data :

https://developers.google.com/maps/documentation/android-api/intents

Example :

Uri gmmIntentUri = Uri.parse("geo:40.007620,-75.160264?q=" + Uri.encode("child hospitals"));

Answer 3

Humty you can try to this code hope this can help you..

Uri gmmIntentUri = Uri.parse("geo:40.007620,-75.160264?z=10&q=child hospitals");
            Intent mapIntent = new Intent(Intent.ACTION_VIEW, gmmIntentUri);
            mapIntent.setPackage("com.google.android.apps.maps");
            startActivity(mapIntent);

Answer 4

You can try something like this :

String urlAddress = 
https://maps.googleapis.com/maps/api/place/nearbysearch/json?location=lat,lng&radius=500&type=city hospital&keyword=hospital&key=YOUR_API_KEY

which you can pass to

Intent intent = new Intent(Intent.ACTION_VIEW, Uri.parse(urlAddress);
startActivity(intent);

This will get opened in Google Maps with the results wrt provided radius. It works also same mentioned in below doc reference.

https://developers.google.com/places/web-service/search

Url to test :

https://maps.googleapis.com/maps/api/place/nearbysearch/json?location=18.590478,73.727191&radius=50000&type=child%20hospital&keyword=child%20hospital&key=PASTE_YOUR_API_KEY