[英]How to select 1st and 2nd row instance in SQL table having the same value in another table?
Sample data: 样本数据:
Output should be: 输出应为:
I want to ask what script in MSSQL I can run to get that kind of output. 我想问一下我可以运行哪种MSSQL脚本来获得这种输出。 Hope somebody can help me I'm still new in SQL programming. 希望有人能帮到我,我对SQL编程还是很陌生。 Thank you so much in advance. 提前非常感谢您。
Use a CTE witha row_number(): 使用带有row_number()的CTE:
with CTE as
(
select T1.*, row_number() over(partition by USERNAME order by TRANSACTION_TIME) X_ORD
from Table1 T1
)
select distinct
A1.USERNAME,
A1.REGISTRATION_DATE,
A2.Transaction_Time as First_X,
A2.RELOAD_AMOUNT as First_R,
A2.CHANNEL as First_C,
A3.Transaction_Time as Second_X,
A3.RELOAD_AMOUNT as Second_R,
A3.CHANNEL as Second_C
from CTE A1
left join CTE A2
on A1.USERNAME = A2.USERNAME
and A2.X_ORD = 1
left join CTE A3
on A1.USERNAME = A3.USERNAME
and A3.X_ORD = 2
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