Java-String.replaceAll返回不同的结果

Question

Here's what I want, there's a string like, CHAR_27[19;50H and I want to get the numbers from the inside separately.

// CHAR_27 = Character.toString( (char)27 );
// Or "\u001B"
String escapeString = "CHAR_27[19;50H";
String coord = escapeString.replaceAll("[^0-9;]", "");
List<String> coords = Splitter.on(";").splitToList(coord);

if (coords.size() != 2) continue;

rowIndex = Integer.parseInt(coords.get(0)) - 1;
colIndex = Integer.parseInt(coords.get(1)) - 1;

But sometimes it throws a NumberFormatException, invalid integer CHAR_27[19 .

Mostly it works fine.

Is there something wrong with my regex?

Or should I use StringUtils.removePattern() for a more consistent result?

I got this report from Nokia_N1 and GT-810(rolex). Both of them are Android 5.1.

And I'm using Android API 24.

Answer 1

The code that you posted will not rise the mentioned exception (if the input is a single line string).

However your code contains some vulnerabilities:

• Orininally separate numbers can be joined by the expression
• Empty strings can be created

I would recommend to use:

String escapeString = "CHAR_27[19;50H";
String[] coords = escapeString.split("[^0-9]+");

if (coords.length != 2) continue;

rowIndex = Integer.parseInt(coords[0]) - 1;
colIndex = Integer.parseInt(coords[1]) - 1;