Hibernate Dynamic @Where子句

Question

I am having @Where at @Table level.

I need to get rows with EffDate field less than current date.

@Entity
@Table(name="party")
@Where(clause="EffDate < " + currentdate())
public class Party implements Serializable {
.......
}

I understand @Where takes constant expression which needs to be provided on compile time. But I need to compare with current date from Java and not from Database.

Any Idea how can I do that.

Answer 1

您可以为当前时间戳使用SQL函数/常量（取决于数据库的类型，例如current_timestamp ）（但是请注意，由于这将是纯SQL，因此它将使用数据库服务器的时间戳，而不是数据库的时间戳）。 Java应用程序在其上运行的服务器：

@Where(clause="EffDate < current_timestamp") 

Answer 2

Write a Hibernate filter and enable it by default for all Sessions in the application. Depending on which framework you use for transaction management, you can add an interceptor/hook that enables the filter when transactions are started.

Answer 3

@Where annotation will not work, since it accepts constant expressions. Instead, I use findOnByEffectiveDateLessThanEquals from JPARepository.

http://docs.spring.io/spring-data/jpa/docs/current/reference/html/#jpa.query-methods.query-creation